clojure 宏来生成函数 [英] clojure macro to generate functions
问题描述
我正在尝试编写一个可以生成 n 个函数的宏.这是我到目前为止所拥有的:
I'm trying to write a macro that will generate n functions. Here's what I have so far:
; only defined this because if I inline this into make-placeholders
; it's unable to expand i# in ~(symbol (str "_" i#))
(defmacro defn-from [str mdata args & body]
`(defn ~(symbol str) ~mdata ~args ~@body))
; use list comprehension to generate n functions
(defmacro make-placeholders [n]
`(for [i# (range 0 ~n)] (defn-from (str "_" i#) {:placeholder true} [& args] (nth args i#))))
; expand functions _0 ... _9
(make-placeholders 9)
我得到的错误是:
java.lang.ClassCastException: clojure.lang.Cons cannot be cast to java.lang.String
而且我不太确定这意味着什么,但我有一个模糊的概念,即(for ...)并没有像我认为的那样在宏中工作.
And I'm not really sure what that means, but I have this vague notion that (for ...) isn't working the way I think it is inside a macro.
推荐答案
您对运行时和编译时以及宏和函数之间的区别感到困惑.使用 eval
解决宏问题永远不是1正确答案:相反,请确保您返回的代码符合您的意愿.这是使您的原始版本正常工作的最小更改.
You are getting confused about the distinction between runtime and compile-time, and between macros and functions. Solving a macro problem with eval
is never1 the right answer: instead, make sure that you return code that does what you want to happen. Here's a minimal change to make your original version work.
主要变化有:
defn-from
是一个函数,而不是一个宏 - 您只需要一种方便的方法来创建列表,主宏负责将其插入到结果表单中.您不需要这里的宏,因为您不希望它扩展到make-placeholders
的主体中.
defn-from
is a function, not a macro - you just want a convenient way to create lists, which the main macro is responsible for inserting into the result form. You do not want a macro here, because you don't want it expanded into the body ofmake-placeholders
.
make-placeholders
以 do
开头,并在语法之外执行它的 for
outside-引用.这是最重要的部分:您希望返回给用户的代码看起来像 (do (defn ...))
,就好像他们是手动输入的一样 - 不是 (for ...)
,它只能定义一个函数.
make-placeholders
starts with a do
, and does its for
outside of a syntax-quote. This is the most important part: you want the code returned to the user to look like (do (defn ...))
, as if they'd typed it all in by hand - not (for ...)
, which could only ever def a single function.
<小时>
(defn defn-from [str mdata args & body]
`(defn ~(symbol str) ~mdata ~args ~@body))
; use list comprehension to generate n functions
(defmacro make-placeholders [n]
(cons `do
(for [i (range 0 n)]
(defn-from (str "_" i) {:placeholder true}
'[& args]
`(nth ~'args ~i)))))
user> (macroexpand-1 '(make-placeholders 3))
(do (clojure.core/defn _0 {:placeholder true} [& args] (clojure.core/nth args 0))
(clojure.core/defn _1 {:placeholder true} [& args] (clojure.core/nth args 1))
(clojure.core/defn _2 {:placeholder true} [& args] (clojure.core/nth args 2)))
1 非常非常罕见
您也可以完全不用宏来完成此操作,方法是使用函数来创建函数并使用低级操作 intern
而不是 def
.事实证明,实际上要简单得多:
You can also do this completely without macros, by using a function to create functions and using the lower-level operation intern
instead of def
. It turns out to be much simpler, in fact:
(letfn [(placeholder [n]
(fn [& args]
(nth args n)))]
(doseq [i (range 5)]
(intern *ns* (symbol (str "_" i))
(placeholder i))))
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