每 45 分钟执行一次 Cron 表达式 [英] Cron expression to be executed every 45 minutes

问题描述

我想要一个每 45 分钟触发一次的 cron 表达式.

I want a cron expression which fires every 45 minutes.

根据文档，我创建了这个 0 0/45 * * * ? 表达式.

According to the documentation, I have created this 0 0/45 * * * ? expression.

但它以 12:00、12:45、13:00、13:45、14:00 这样的模式触发.

But it is fired in a pattern like 12:00, 12:45, 13:00, 13:45, 14:00.

但我期望和想要的是在 12:00、12:45、13:30、14:15 被解雇.

But what I expect and want is to be fired at 12:00, 12:45, 13:30, 14:15.

我错过了什么?

推荐答案

Cron 并不是为了解决此类问题.它定义了必须触发触发器的确切日期和时间，而不是时间间隔.改用简单的时间表:

Cron is not meant to solve such problems. It defines the exact date and times, when a trigger must be fired, not intervals. Use a simple schedule instead:

TriggerBuilder.Create()
  .StartAt(startDate)
  .WithSimpleSchedule(
    simpleScheduleBuilder => simpleScheduleBuilder.WithIntervalInMinutes(45))
  .Build();

它要么是上面的简单计划，要么是多个 cron 触发器(Quartz 作业可以有多个触发器):

It's either a simple schedule as above, or multiple cron triggers (Quartz jobs can have multiple triggers):

0 0/45 12/3 * * ?    # 12:00, 12:45, 15:00, 15:45, ...
0 30 13/3 * * ?      # 13:30, 16:30, ...
0 15 14/3 * * ?      # 14:15, 17:15, ...

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