如何创建 HTTP GET 请求 Scapy? [英] How to create HTTP GET request Scapy?

问题描述

我需要创建 HTTP GET 请求并保存数据响应.我试着用这个:

I need to create HTTP GET request and save the data response. I tried to use this:

    syn = IP(dst=URL) / TCP(dport=80, flags='S')
    syn_ack = sr1(syn)
    getStr = 'GET / HTTP/1.1
Host: www.google.com

'
    request = IP(dst='www.google.com') / TCP(dport=80, sport=syn_ack[TCP].dport,
            seq=syn_ack[TCP].ack, ack=syn_ack[TCP].seq + 1, flags='A') / getStr
    reply = sr1(request)
    print reply.show()

但是当我打印 reply 时，我没有看到任何数据响应.此外，当我签入Wireshark"时，我收到了 SYN、SYN/ACK，但没有收到 ACK.

But when I print reply I don't see any data response. In addition, when I checked in 'Wireshark' I got SYN, SYN/ACK but I didn't get an ACK.

图片:

我现在尝试这样做:

# Import scapy
from scapy.all import *

# Print info header
print "[*] ACK-GET example -- Thijs 'Thice' Bosschert, 06-06-2011"

# Prepare GET statement
get='GET / HTTP/1.0

'

# Set up target IP
ip=IP(dst="www.google.com")

# Generate random source port number
port=RandNum(1024,65535)

# Create SYN packet
SYN=ip/TCP(sport=port, dport=80, flags="S", seq=42)

# Send SYN and receive SYN,ACK
print "
[*] Sending SYN packet"
SYNACK=sr1(SYN)

# Create ACK with GET request
ACK=ip/TCP(sport=SYNACK.dport, dport=80, flags="A", seq=SYNACK.ack, ack=SYNACK.seq + 1) / get

# SEND our ACK-GET request
print "
[*] Sending ACK-GET packet"
reply,error=sr(ACK)

# print reply from server
print "
[*] Reply from server:"
print reply.show()

print '
[*] Done!'

但是它打印我作为服务器的回复；

but its print me in reply from server;

0000 IP/TCP 192.168.44.130:23181 > 216.58.208.164:http A/Raw ==>IP/TCP 216.58.208.164:http > 192.168.44.130:23181 A/Padding None

0000 IP / TCP 192.168.44.130:23181 > 216.58.208.164:http A / Raw ==> IP / TCP 216.58.208.164:http > 192.168.44.130:23181 A / Padding None

我需要基于行的文本数据:text/html.

And I need Line-based text data: text/html.

推荐答案

您正在发送 SYN 并正确接收 SYN_ACK.此时，您应该根据您收到的 SYN_ACK 生成并发送一个 ACK​​，然后最终发送 HTTP GET 请求.看来你对TCP 3次握手机制有些困惑.简而言之，您不应该获得"ACK，您应该自己生成并发送.

You are sending a SYN and correctly receiving a SYN_ACK. At this point, you should generate and send an ACK based on the SYN_ACK that you've received, and THEN finally transmit the HTTP GET request. It seems that you are somewhat confused about the TCP 3-way handshake mechanism. In short, you are not supposed to 'get' an ACK, you are supposed to generate and send this yourself.

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