单个函数关闭所有打开的视图控制器 [英] single function to dismiss all open view controllers

问题描述

我有一个应用程序，它是一个单视图应用程序.我有一个导航控制器链接到根视图控制器的所有子控制器.

I have an app which is a single view application. I have a navigation controller linked up to all child controllers from the root view controller.

在每个子控制器中，我都有一个注销按钮.我想知道我是否可以有一个可以调用的函数，该函数将关闭一路上打开的所有控制器，无论用户按下注销时当前打开的是哪个控制器?

In each child controller, I have a logout button. I'm wondering if I can have a single function I can call which will dismiss all the controllers which have been open along along the way, no matter which controller was currently open when the user presses logout?

我的基本开始:

func tryLogout(){
     self.dismissViewControllerAnimated(true, completion: nil)
     let navigationController = UINavigationController(rootViewController: UIStoryboard(name: "Main", bundle: nil).instantiateViewControllerWithIdentifier("LoginViewController") )
     self.presentViewController(navigationController, animated: true, completion: nil)
}

我正在寻找执行此任务的最节省内存的方法.我会将我的注销功能放在一个单独的 utils 文件中，但是我不能使用 self.而且我仍然无法知道要动态关闭哪些控制器.

I am looking for the most memory efficient way of carrying out this task. I will put my logout function in a separate utils file, but then I can't use self. And I still have the issue of knowing which controllers to dismiss dynamically.

更新已建议弹出到根视图控制器.所以我的尝试是这样的:

Update Pop to root view controller has been suggested. So my attempt is something like:

func tryLogout(ViewController : UIViewController){
     print("do something")
     dispatch_async(dispatch_get_main_queue(), {
         ViewController.navigationController?.popToRootViewControllerAnimated(true)
         return
     })
 }

这是实现我所追求的最佳方式吗?

Would this be the best way to achieve what I'm after?

推荐答案

您可以拨打:

self.view.window!.rootViewController?.dismiss(animated: false, completion: nil)

应该关闭根视图控制器之上的所有视图控制器.

Should dismiss all view controllers above the root view controller.

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