在 C 中等待中断的有效方法 [英] Efficient way to wait for an interrupt in C

问题描述

我在树莓派上使用 WiringPi.有了它，我分配了一个稍后调用的中断函数.我不知道在等待中断被调用时该怎么做.

I am using WiringPi on a raspberry pi. With it I assign an interrupt function which is called later. I'm not sure what to do when waiting for the interupt to be called.

示例使用 (spinlock?) for (;;) 例如

Examples use a (spinlock?) for (;;) e.g.

int main()
{
    // register interrupt
    wiringPiISR( 18, INT_EDGE_BOTH, &myInterrupt );

    for (;;) {
        // really?
    }
    return 0;
}

而且我注意到 sleep 也有效.无论睡眠如何，都会调用中断

And I noticed that sleep works too. The interrupt is called regardless of the sleep

int main() 
{
    // register interrupt
    wiringPiISR( 18, INT_EDGE_BOTH, &myInterrupt );

    for (;;) {
        sleep(1000000);
    }
    return 0;
}

使用最少的资源保持程序运行的最佳做法是什么(假设这是用于后台恶魔)?

What is the best practise to keep the program running, using minimal resources (say if this were for a background demon)?

来自其他语言，我原以为 for(;;) 会消耗资源.我想知道要做什么或要做什么的指示(线程等).

Coming from other languages, I would have thought for(;;) would eat up resources. I would like to know what to do or pointers on what to do (threads etc).

推荐答案

我最近不得不这样做.我的理论是KISS.sleep 被定义为使用最少的资源 - 使用它意味着我不必关心线程.

I recently had to do exactly this. My theory was KISS. sleep is written to use minimal resources by definition - and using it means I don't have to care about threads.

简单、可读且对原始 Raspberry Pi B 没有可测量的性能影响:

Simple, readable and no measurable performance hit on an original Raspberry Pi B:

int main() 
{
    // register interrupt
    wiringPiISR( 18, INT_EDGE_BOTH, &myInterrupt );

    for (;;) {
        sleep(UINT_MAX);
    }
    return 0;
}

请注意使用 UINT_MAX 来最小化 for 循环调用的次数 - 这假设 WiringPi 使用的无符号 32 位定时器延迟.

Note the use of UINT_MAX to minimise number of for loop calls - this assumes an unsigned 32-bit timer delay, which is what WiringPi uses.

这篇关于在 C 中等待中断的有效方法的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！