Django 模板:创建一个“back"关联? [英] Django templates: create a "back" link?
问题描述
我正在使用 Django,我想知道是否有一种简单的方法来创建一个使用模板系统返回"链接到上一页.
我认为在最坏的情况下,我可以从视图函数中的请求对象中获取此信息,并将其传递给模板渲染方法,但我希望我可以以某种方式避免所有这些样板代码.>
我已经检查了 Django 模板文档,但没有看到任何明确提到这一点的内容.
你可以启用:
'django.core.context_processors.request',
在您的 settings.TEMPLATE_CONTEXT_PROCESSORS
块中并勾出引荐来源网址,但这有点令人作呕,并且可能会到处崩溃.
大多数你想要这个的地方(例如 SO 上的编辑帖子页面)你有一个真实的对象可以连接到(在那个例子中,帖子)所以你可以轻松地计算出正确的前一页应该是什么.
I'm tooling around with Django and I'm wondering if there is a simple way to create a "back" link to the previous page using the template system.
I figure that in the worst case I can get this information from the request object in the view function, and pass it along to the template rendering method, but I'm hoping I can avoid all this boilerplate code somehow.
I've checked the Django template docs and I haven't seen anything that mentions this explicitly.
Well you can enable:
'django.core.context_processors.request',
in your settings.TEMPLATE_CONTEXT_PROCESSORS
block and hook out the referrer but that's a bit nauseating and could break all over the place.
Most places where you'd want this (eg the edit post page on SO) you have a real object to hook on to (in that example, the post) so you can easily work out what the proper previous page should be.
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