PHP GuzzleHttp.如何使用参数进行发布请求? [英] PHP GuzzleHttp. How to make a post request with params?

问题描述

如何使用 GuzzleHttp(5.0 版)发出 post 请求.

How to make a post request with GuzzleHttp( version 5.0 ).

我正在尝试执行以下操作:

I am trying to do the following:

$client = new GuzzleHttpClient();
$client->post(
    'http://www.example.com/user/create',
    array(
        'email' => '[e-mail]',
        'name' => 'Test user',
        'password' => 'testpassword'
    )
);

但我收到错误:

PHP 致命错误:未捕获的异常InvalidArgumentException"，消息为No method can handle the email config key"

PHP Fatal error: Uncaught exception 'InvalidArgumentException' with the message 'No method can handle the email config key'

推荐答案

试试这个

$client = new GuzzleHttpClient();
$client->post(
    'http://www.example.com/user/create',
    array(
        'form_params' => array(
            'email' => '[e-mail]',
            'name' => 'Test user',
            'password' => 'testpassword'
        )
    )
);

这篇关于PHP GuzzleHttp.如何使用参数进行发布请求?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！