如何在不需要先绘画的情况下获得位图透明度? [英] How to get bitmap transparancy without the need to paint first?
问题描述
默认情况下,新创建的位图似乎具有(白色)背景.至少,对 Pixels 属性的查询证实了这一点.但是为什么当 Transparent
设置为 true 时,背景颜色不用作透明颜色?
A newly created bitmap seems to have a (white) background by default. At least, a query on the Pixels property confirms. But why is that background color not used as the transparent color when Transparent
is set true?
考虑这个简单的测试代码:
Consider this simple test code:
procedure TForm1.Button1Click(Sender: TObject);
var
Bmp: TBitmap;
begin
Bmp := TBitmap.Create;
try
Bmp.Width := 100;
Bmp.Height := 100;
Bmp.Transparent := True;
Canvas.Draw(0, 0, Bmp); // A white block is drawn
Bmp.Canvas.Brush.Color := Bmp.Canvas.Pixels[0, 99]; // = 'clWhite'
Bmp.Canvas.FillRect(Rect(0, 0, 100, 100));
Canvas.Draw(0, 100, Bmp); // "Nothing" is drawn
finally
Bmp.Free;
end;
end;
出于某种原因,整个位图表面必须先绘制才能显示为透明,这听起来有点奇怪.
For some reason, the entire bitmap surface has to be painted before it can appear transparent, which sounds kind of odd.
尝试以下变体来消除对 FillRect
的调用,所有结果都相同(无透明度):
The following variations are tried to eliminate the call to FillRect
, all with the same outcome (no transparancy):
- 只设置
Brush.Color
, Brush.Handle := CreateSolidBrush(clWhite)
,PixelFormat := pf32Bit
,IgnorePalette := True
,TransparantColor := clWhite
,TransparantMode := tmFixed
,Canvas.Pixels[0, 99] := clWhite
只让那个像素透明,修改:= True
.
- Only setting
Brush.Color
, Brush.Handle := CreateSolidBrush(clWhite)
,PixelFormat := pf32Bit
,IgnorePalette := True
,TransparantColor := clWhite
,TransparantMode := tmFixed
,Canvas.Pixels[0, 99] := clWhite
which makes only thát pixel transparent,Modified := True
.
因此,我们希望只绘制新创建的位图的一部分,并使剩余的表面透明.
So, the wish is to paint only a portion of a newly created bitmap and get the remaining surface transparent.
使用:Delphi 7,Win 7/64.
Using: Delphi 7, Win 7/64.
推荐答案
在设置位图的尺寸之前只需设置 TransparentColor 和 Canvas.Brush.Color.
Just set TransparentColor and Canvas.Brush.Color before setting dimensions of the bitmap.
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