我的基于 AMD 的机器使用小端还是大端? [英] Does my AMD-based machine use little endian or big endian?

问题描述

我正在学习计算机系统课程，并且我正在尝试确定，肯定，如果我的基于 AMD 的计算机是小端机器?我相信这是因为它将与英特尔兼容.

I'm going though a computers system course and I'm trying to establish, for sure, if my AMD based computer is a little-endian machine? I believe it is because it would be Intel-compatible.

具体来说，我的处理器是 AMD 64 Athlon x2.

Specifically, my processor is an AMD 64 Athlon x2.

我知道这在 C 编程中很重要.我正在编写 C 程序，我正在使用的方法会受此影响.我想弄清楚如果我在基于 Intel 的机器上运行程序是否会得到相同的结果(假设是小端机器).

I understand that this can matter in C programming. I'm writing C programs and a method I'm using would be affected by this. I'm trying to figure out if I'd get the same results if I ran the program on an Intel based machine (assuming that is little endian machine).

最后，让我问一下:任何和所有能够运行 Windows(XP、Vista、2000、Server 2003 等)的机器，比如 Ubuntu Linux 桌面是小端吗?

Finally, let me ask this: Would any and all machines capable of running Windows (XP, Vista, 2000, Server 2003, etc) and, say, Ubuntu Linux desktop be little endian?

推荐答案

所有 x86 和 x86-64 机器(只是 x86 的扩展)都是小端的.

All x86 and x86-64 machines (which is just an extension to x86) are little-endian.

您可以通过以下方式确认:

You can confirm it with something like this:

#include <stdio.h>
int main() {
    int a = 0x12345678;
    unsigned char *c = (unsigned char*)(&a);
    if (*c == 0x78) {
       printf("little-endian
");
    } else {
       printf("big-endian
");
    }
    return 0;
}

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