把一个BigIntegers返回双 [英] Dividing a BigIntegers to return double

问题描述

欲计算直线的斜率

public sealed class Point
{
    public System.Numerics.BigInteger x = 0;
    public System.Numerics.BigInteger y = 0;

    public double CalculateSlope (Point point)
    {
        return ((point.Y - this.Y) / (point.X - this.X));
    }
}

我知道的BigInteger具有DivRem函数，返回除法结果再加上余，但我不知道如何运用它来得到一个双。我处理的数字是远远超越Int64.MaxValue的范围，其余本身可能是超出范围，计算按常规划分。

I know that BigInteger has a DivRem function that returns the division result plus the remainder but am not sure how to apply it to get a double. The numbers I'm dealing with are far far beyond the range of Int64.MaxValue so the remainder itself could be out of range to calculate by conventional division.

修改： 不知道是否有帮助，但我只用正整数处理（> = 1）。

EDIT: Not sure if it helps but I'm dealing with only positive integers (>=1).

重要：我只需要precision几个小数点（5应该是对我来说已经足够了）

IMPORTANT: I only need a few decimal points of precision (5 should be good enough for my purpose).

推荐答案

在 BigRational 库有一个转换操作符翻一番。

The BigRational library has a conversion operator to double.

另外，要记住将无穷大作为特殊情况下的垂直线，你会得到一个被零除例外情况与当前的code。也许最好只计算X1 - X2第一，并返回无穷大，如果是零，然后做了分工，避免重复操作

Also, remember to return infinity as a special case for a vertical line, you'll get a divide by zero exception with your current code. Probably best to just calculate the X1 - X2 first, and return infinity if it's zero, then do the division, to avoid redundant operations.

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