MVC4行动返回JsonResult没有空 [英] MVC4 Action returning JsonResult without null
问题描述
我有返回JsonResult特定类的对象的动作。我装饰了这个类的属性与一些ATTRIB,以避免空字段。类定义是:
I have a action which returns an JsonResult for an object of a particular class. I have decorated the properties of this class with some attrib to avoid null fields. Class definition is:
private class GanttEvent
{
public String name { get; set; }
[JsonProperty(NullValueHandling = NullValueHandling.Ignore)]
public String desc { get; set; }
[JsonProperty(NullValueHandling = NullValueHandling.Ignore)]
public List<GanttValue> values { get; set; }
}
在我行动我使用一个对象
And in my Action i use an object
var res = new List<GanttEvent>();
我将带回使用:
return Json(res, JsonRequestBehavior.AllowGet);
可惜的是,我仍然在输出接收空值:
Unfortunatelly, I'm still receiving null values at output:
[{"name":"1.1 PREVIOS AL INICIO ","desc":null,"values":null},{"name":"F04-PGA-S10","desc":"Acta preconstrucción","values":null},{"name":"F37-PGA-S10","desc":"Plan de inversión del anticipo","values":null},{"name":"F09-PGA-S10","desc":"Acta de vecindad","values":null},{"name":"F05-PGA-S10","desc":"Acta de inicio","values":null},{"name":"F01-PGA-S10","desc":"Desembolso de anticipo","values":null}]
我缺少的东西,或做错了什么?
Am I missing something or doing something wrong?
推荐答案
如前所述布拉德·克里斯蒂,MVC4剧照使用的JavaScriptSerializer,所以为了让你的对象由Json.Net序列化,你将必须执行几个步骤。
As stated by Brad Christie, MVC4 stills uses JavaScriptSerializer, so in order to get your object serialized by Json.Net, you will have to perform several steps.
首先,继承JsonResult一个新的类JsonNetResult如下(根据<一个href=\"http://stackoverflow.com/questions/6883204/change-default-json-serializer-used-in-asp-mvc3\">this解决方案):
First, inherit a new class JsonNetResult from JsonResult as follows (based on this solution):
public class JsonNetResult : JsonResult
{
public JsonNetResult()
{
this.ContentType = "application/json";
}
public JsonNetResult(object data, string contentType, Encoding contentEncoding, JsonRequestBehavior jsonRequestBehavior)
{
this.ContentEncoding = contentEncoding;
this.ContentType = !string.IsNullOrWhiteSpace(contentType) ? contentType : "application/json";
this.Data = data;
this.JsonRequestBehavior = jsonRequestBehavior;
}
public override void ExecuteResult(ControllerContext context)
{
if (context == null)
throw new ArgumentNullException("context");
var response = context.HttpContext.Response;
response.ContentType = !String.IsNullOrEmpty(ContentType) ? ContentType : "application/json";
if (ContentEncoding != null)
response.ContentEncoding = ContentEncoding;
if (Data == null)
return;
// If you need special handling, you can call another form of SerializeObject below
var serializedObject = JsonConvert.SerializeObject(Data, Formatting.None);
response.Write(serializedObject);
}
}
然后,在你的控制器,覆盖JSON的方法来使用新的类:
Then, in your controller, override the Json method to use the new class:
protected override JsonResult Json(object data, string contentType, Encoding contentEncoding, JsonRequestBehavior behavior)
{
return new JsonNetResult(data, contentType, contentEncoding, behavior);
}
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