Android - loopJ AsyncHttpClient 返回响应 onFinish 或 onSuccess [英] Android - loopJ AsyncHttpClient return response onFinish or onSuccess

问题描述

我正在寻找一种方法来返回我在 loopJ AsyncHttpClient onFinish 或 onSuccess 或 onFailure 中得到的响应.截至目前，我有这段代码:

I am looking for a way to return the response I get in loopJ AsyncHttpClient onFinish or onSuccess or onFailure. As of now I have this piece of code:

**jsonParse.java file**
public class jsonParse {
    static JSONObject jObj = null;
    static String jsonString = "";
    AsyncHttpClient client;

      public JSONObject getJSONObj() {
            RequestParams params;
            params = new RequestParams();
            params.add("username", "user");
            params.add("password", "password");
            client = new AsyncHttpClient();
            client.post("http://example.com", params, new TextHttpResponseHandler() {

                @Override
                public void onSuccess(int i, Header[] headers, String response) {
                    jsonString = response;
                    Log.d("onSuccess: ", jsonString);
                }

                @Override
                public void onFailure(int statusCode, Header[] headers, String response, Throwable e) {
                    if (statusCode == 401) {
                        jsonString = response;
                        Log.d("onFailure: ", jsonString);
                    }
                }

            });
            try {
                jObj = new JSONObject(jsonString);
            } catch (JSONException e) {
                Log.e("Exception", "JSONException " + e.toString());
            }
            return jObj;
        }
}

当我调用代码时:

JSONParser jsonParser = new JSONParser();
jsonParser.getJSONFromUrl(); 

我在 onSuccess 或 onFailure 方法完成 http 帖子之前收到 JSONException.

I get the JSONException before onSuccess or onFailure method finishes the http post.

我注意到，在第一次调用时:Log.e("异常", "JSONException" + e.toString());正在记录然后 Log.d("onSuccess: ", jsonString);记录处于同步状态的值.

I have noticed that, on the first invoke: Log.e("Exception", "JSONException " + e.toString()); is getting logged and then Log.d("onSuccess: ", jsonString); logs the value as they are in the sync state.

在第二次调用时:jObj = 新的 JSONObject(jsonString);成功执行并且我获得了该方法所需的返回值，因为到那时 onSuccess 方法已经将值分配给变量 jsonString.

On the second invoke: jObj = new JSONObject(jsonString); gets executed successfully and I get desired return value for the method, because by that time onSuccess method would have already assigned the value to the variable jsonString.

现在我正在寻找的是一种防止jObj从方法中过早返回的方法.

Now what I am exactly looking for is a way to prevent premature return of jObj from the method.

有没有办法让方法getJSONObj，等待AsyncHttpClient任务完成，将变量赋值给jsonString，创建JSONObject并返回?

提前致谢！干杯！

推荐答案

使用接口.通过这种方式，您可以创建自己的回调，其方法可以从 onSuccess 或 onFailure 调用.

Use an interface. This way you can create your own callback whose methods can be called from onSuccess or onFailure.

public interface OnJSONResponseCallback {
    public void onJSONResponse(boolean success, JSONObject response);
}

public JSONObject getJSONObj(OnJSONResponseCallback callback) {
    ...
   @Override
   public void onSuccess(int i, Header[] headers, String response) {
       try {
           jObj = new JSONObject(response);
           callback.onJSONResponse(true, jObj);
       } catch (JSONException e) {
           Log.e("Exception", "JSONException " + e.toString());
       }
   }

   @Override
   public void onFailure(int statusCode, Header[] headers, String response, Throwable e) {
       try {
           jObj = new JSONObject(response);
           callback.onJSONResponse(false, jObj);
       } catch (JSONException e) {
           Log.e("Exception", "JSONException " + e.toString());
       }
   }
}

并调用它:

jsonParse.getJSONObj(new OnJSONResponseCallback(){
    @Override
    public void onJSONResponse(boolean success, JSONObject response){
       //do something with the JSON
    }
});

这篇关于Android - loopJ AsyncHttpClient 返回响应 onFinish 或 onSuccess的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！