laravel 4 分页集合 [英] laravel 4 paginate collection

问题描述

我无法使用 laravel 4 创建适当的分页系统.我有以下模型和函数返回集合:

I cant create a proper pagination system using laravel 4. I have the following models and function that return collections:

模范餐厅:

public function fooditem()
{
    return $this->hasMany('Fooditem','rest_id');
}
public function get_rest_foods($id){
    return Restaurant::find($id)->fooditem->toArray();
}

第二个函数以数组的形式返回某个餐厅的所有食物.我也在 API 调用中使用它.

The second function returns all food items for a certain restaurant as an array. I also use this in an API call.

在我的控制器中我有这个:

in my controller i have this:

 $food = $food->get_rest_foods($id);
 $paginator = Paginator::make($food, 10, 5);

我将分页器传递给视图，它显示链接正常，但也显示了食物数组中的所有项目.

I pass the paginator to the view and it shows the links ok but also shows all my item from the food array.

我尝试过使用

public function get_rest_foods($id){
        return Restaurant::find($id)->fooditem->paginate(5);
    }

但我得到一个错误:

FatalErrorException: 错误:调用未定义的方法 IlluminateDatabaseEloquentCollection::paginate()

FatalErrorException: Error: Call to undefined method IlluminateDatabaseEloquentCollection::paginate()

我搜索了这个网站和许多其他网站，但不明白如何对集合进行分页.

I searched this and many other sites but cant understant how to paginate a collection.

感谢您的帮助

推荐答案

分页器必须获取它通常会使用偏移/限制语句从数据库查询中获取的项目.所以当你有一个包含所有项目的集合时，你应该自己做偏移/限制.

The paginator must get the items that it would normally get from a database query with an offset/limit statement. So when you have a collection with all items, you should do the offset/limit yourself.

    $food = $food->get_rest_foods($id);

    $page = 1;
    if( !empty(Input::get['page']) ) {
        $page = Input::get['page'];
    }

    $perPage = 15;
    $offset = (($page - 1) * $perPage);

    $food = Paginator::make($food->slice($offset,$perPage, true)->all(), $food->count(), $perPage);

这篇关于laravel 4 分页集合的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！