在 MSBuild 中将程序集版本号指定为命令行参数 [英] Specify assembly version number as a command line argument in MSBuild

问题描述

我希望能够将构建期间生成的所有程序集的版本号指定为 MSBuild 命令参数，如下所示:

I would like to be able to specify the version number for all assemblies to be generated during a build as a MSBuild command argument like this:

MSBuild.exe /p:version=5.4.3.0 

我已经查看了 AssemblyInfoTask，但在我看来，在这种情况下它并不是一个好的解决方案.

I have looked over AssemblyInfoTask but it does not seem to me like a good solution in this case.

推荐答案

我一直使用您在评论中描述的 AssemblyInfo 任务.

I use the AssemblyInfo task as you describe in your comment all the time.

  <!-- update standard assembly attribute in all projects -->
  <Target Name="BeforeBuild" >
    <Message Text="Updating AssemblyInfo to Version $(VersionNumber)"></Message>
    <Message Text="Writing to AssemblyInfo files in $(SolutionRoot)"></Message>
    <AssemblyInfo AssemblyInfoFiles="@(AssemblyInfoFiles)" 
                  AssemblyCopyright="$(AssemblyCopyright)" 
                  AssemblyVersion="$(VersionNumber)"
                  AssemblyFileVersion="$(VersionNumber)"
                  >
    </AssemblyInfo>
  </Target>

VersionNumber 值完全按照您的描述从 MSBuild 项目文件外部传递:

The VersionNumber value is passed from outside the MSBuild project file exactly as you describe:

  MSBuild <project_file> /p:VersionNumber=<value>;...

我们使用 BeforeBuild 目标来确保 AssemblyInfo.cs 文件在构建开始之前得到处理.这不是你想要的吗?

We use the BeforeBuild target to ensure the AssemblyInfo.cs files all get worked on before the build starts. Is this not what you want?

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