单击弹出框触发元素时，如何关闭/关闭 Bootstrap 弹出框? [英] How can I close / dismiss Bootstrap Popover when clicking the popover trigger element?

问题描述

jsFiddle:

以下是有效的:

1. 点击按钮打开弹出框
2. 在弹出框外点击关闭弹出框
3. 点击.close按钮关闭弹出框

但是...当您再次单击原始按钮时，我无法关闭弹出框.相反，弹出框会闪烁并再次闪烁.

自己复制这里.

我怎样才能做到这一点?

HTML:

<button id="popoverId" class="popoverThis btn btn-large btn-danger">点击切换popover</button><div id="popoverContent" class="hide">这个<em>丰富</em><pre>html</pre>内容进入弹出框</div>

JS:

$('#popoverId').popover({html: 是的,标题:弹出标题"，内容:函数(){返回 $('#popoverContent').html();}});var isVisible = false;var clickedAway = false;$('.popoverThis').popover({html: 是的,触发器:'手动'}).click(函数 (e) {$(this).popover('show');$('.popover-content').append('<a class="close" style="position: absolute; top: 0; right: 6px;">&times;</a>');clickedAway = falseisVisible = 真e.preventDefault()});$(文档).click(函数 (e) {if (isVisible & clickedAway) {$('.popoverThis').popover('隐藏')isVisible = clickedAway = false} 别的 {clickedAway = true}});

解决方案

你想要这样的工作吗?

http://jsfiddle.net/kAYyR/3/

$('#popoverId').popover({html: 是的,title: '弹出框标题<a class="close" href="#");">&times;</a>',内容:$('#popoverContent').html(),});$('#popoverId').click(function (e) {e.stopPropagation();});$(文档).click(函数 (e) {if (($('.popover').has(e.target).length == 0) || $(e.target).is('.close')) {$('#popoverId').popover('hide');}});

jsFiddle: http://jsfiddle.net/kAYyR/

Screenshot:

Here's what works:

1. Open popover on button click
2. Close popover on click outside popover
3. Close popover on click of .close button

BUT... I cannot get the popover to close when you click the original button again. Instead the popover flashes off and on again.

Duplicate it yourself here.

How can I accomplish this?

HTML:

<button id="popoverId" class="popoverThis btn btn-large btn-danger">Click to toggle popover</button>
<div id="popoverContent" class="hide">This <em>rich</em> <pre>html</pre> content goes inside popover</div>

JS:

$('#popoverId').popover({
    html: true,
    title: "Popover Title",
    content: function () {
        return $('#popoverContent').html();
    }
});


var isVisible = false;
var clickedAway = false;

$('.popoverThis').popover({
    html: true,
    trigger: 'manual'
}).click(function (e) {
    $(this).popover('show');
    $('.popover-content').append('<a class="close" style="position: absolute; top: 0; right: 6px;">&times;</a>');
    clickedAway = false
    isVisible = true
    e.preventDefault()
});

$(document).click(function (e) {
    if (isVisible & clickedAway) {
        $('.popoverThis').popover('hide')
        isVisible = clickedAway = false
    } else {
        clickedAway = true
    }
});

解决方案

Do you want work like this ?

http://jsfiddle.net/kAYyR/3/

$('#popoverId').popover({
    html: true,
    title: 'Popover Title<a class="close" href="#");">&times;</a>',
    content: $('#popoverContent').html(),
});

$('#popoverId').click(function (e) {
    e.stopPropagation();
});

$(document).click(function (e) {
    if (($('.popover').has(e.target).length == 0) || $(e.target).is('.close')) {
        $('#popoverId').popover('hide');
    }
});

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