将文件从 Javascript 上传到 PHP [英] Pass file from Javascript upload to PHP
本文介绍了将文件从 Javascript 上传到 PHP的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我正在编写一个脚本，让用户上传文件并查看上传状态，然后将文件保存在服务器上.
问题是我无法使用 php api.所以我想用javascript上传文件，在那里我可以轻松获得上传状态，但我想将文件传递给php并保存.
这可能吗?
这是要上传的 javascript 代码.
<!DOCTYPE html><html><头><title>使用 XMLHttpRequest 上传文件</title><脚本类型="文本/javascript">功能文件选择(){var file = document.getElementById('fileToUpload').files[0];如果(文件){var 文件大小 = 0;如果(文件大小> 1024 * 1024)fileSize = (Math.round(file.size * 100/(1024 * 1024))/100).toString() + 'MB';别的fileSize = (Math.round(file.size * 100/1024)/100).toString() + 'KB';document.getElementById('fileName').innerHTML = '名称:' + file.name;document.getElementById('fileSize').innerHTML = 'Size: ' + fileSize;document.getElementById('fileType').innerHTML = '类型:' + file.type;}}函数上传文件(){var fd = new FormData();fd.append("fileToUpload", document.getElementById('fileToUpload').files[0]);var xhr = new XMLHttpRequest();xhr.upload.addEventListener("进度", uploadProgress, false);xhr.addEventListener("加载", uploadComplete, false);xhr.addEventListener("错误", uploadFailed, false);xhr.addEventListener("abort", uploadCanceled, false);xhr.open("POST", "UploadHandler.ashx");xhr.send(fd);}函数上传进度(evt){如果(evt.lengthComputable){var percentComplete = Math.round(evt.loaded * 100/evt.total);document.getElementById('progressNumber').innerHTML = percentComplete.toString() + '%';document.getElementById('prog').value = percentComplete;}别的 {document.getElementById('progressNumber').innerHTML = '无法计算';}}函数上传完成(evt){/* 当服务器发回响应时引发此事件 */警报(evt.target.responseText)；}函数上传失败(evt){alert("上传文件时出错.");}函数上传取消(evt){alert("上传已被用户取消或浏览器断开连接.");}</脚本></头><身体><form id="form1"><label for="fileToUpload">选择要上传的文件</label><input type="button" onclick="uploadFile()" value="Upload"/></div><div id="progressNumber"></div><progress id="prog" value="0" max="100.0"></progress></表格></身体></html> 解决方案 我对此有一个Gist.它使用 xhr.send(FormData) 并显示最少的代码用 PHP 处理文件.
I'm working on a script to let the user upload a file and sees a upload status and the file is then saved on the server.
The problem is that I cannot use the php api. So I was thinking to upload the file with javascript where I can easly get the upload status but then I want to pass the file to php and save it.
Is this possible?
This is the javascript code to upload.
<!DOCTYPE html>
<html>
<head >
<title>Upload Files using XMLHttpRequest</title>
<script type="text/javascript">
function fileSelected() {
var file = document.getElementById('fileToUpload').files[0];
if (file) {
var fileSize = 0;
if (file.size > 1024 * 1024)
fileSize = (Math.round(file.size * 100 / (1024 * 1024)) / 100).toString() + 'MB';
else
fileSize = (Math.round(file.size * 100 / 1024) / 100).toString() + 'KB';
document.getElementById('fileName').innerHTML = 'Name: ' + file.name;
document.getElementById('fileSize').innerHTML = 'Size: ' + fileSize;
document.getElementById('fileType').innerHTML = 'Type: ' + file.type;
}
}
function uploadFile() {
var fd = new FormData();
fd.append("fileToUpload", document.getElementById('fileToUpload').files[0]);
var xhr = new XMLHttpRequest();
xhr.upload.addEventListener("progress", uploadProgress, false);
xhr.addEventListener("load", uploadComplete, false);
xhr.addEventListener("error", uploadFailed, false);
xhr.addEventListener("abort", uploadCanceled, false);
xhr.open("POST", "UploadHandler.ashx");
xhr.send(fd);
}
function uploadProgress(evt) {
if (evt.lengthComputable) {
var percentComplete = Math.round(evt.loaded * 100 / evt.total);
document.getElementById('progressNumber').innerHTML = percentComplete.toString() + '%';
document.getElementById('prog').value = percentComplete;
}
else {
document.getElementById('progressNumber').innerHTML = 'unable to compute';
}
}
function uploadComplete(evt) {
/* This event is raised when the server send back a response */
alert(evt.target.responseText);
}
function uploadFailed(evt) {
alert("There was an error attempting to upload the file.");
}
function uploadCanceled(evt) {
alert("The upload has been canceled by the user or the browser dropped the connection.");
}
</script>
</head>
<body>
<form id="form1">
<div>
<label for="fileToUpload">
Select a File to Upload</label>
<input type="file" name="fileToUpload[]" id="fileToUpload" onchange="fileSelected();" />
</div>
<div id="fileName">
</div>
<div id="fileSize">
</div>
<div id="fileType">
</div>
<div>
<input type="button" onclick="uploadFile()" value="Upload" />
</div>
<div id="progressNumber">
</div>
<progress id="prog" value="0" max="100.0"></progress>
</form>
</body>
</html>
解决方案 I have a Gist on this. It uses xhr.send(FormData) and shows minimal code
to handle the file in PHP.
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