JQuery:删除重复元素? [英] JQuery: Remove duplicate elements?

问题描述

假设我有一个包含重复值的链接列表，如下所示:

Say I have a list of links with duplicate values as below:

<a href="#">Book</a>
<a href="#">Magazine</a>
<a href="#">Book</a>
<a href="#">Book</a>
<a href="#">DVD</a>
<a href="#">DVD</a>
<a href="#">DVD</a>
<a href="#">Book</a>

我将如何使用 JQuery 删除 dups 并留下以下示例:

How would I, using JQuery, remove the dups and be left with the following for example:

<a href="#">Book</a>
<a href="#">Magazine</a>
<a href="#">DVD</a>

基本上，我正在寻找一种方法来删除找到的任何重复值并显示每个链接的 1 个.

Basically I am looking for a way to remove any duplicate values found and show 1 of each link.

推荐答案

var seen = {};
$('a').each(function() {
    var txt = $(this).text();
    if (seen[txt])
        $(this).remove();
    else
        seen[txt] = true;
});

说明:

seen 是一个将任何先前看到的文本映射到 true 的对象.它作为一个 集合 包含所有以前看到的文本.if (seen[txt]) 行检查文本是否在集合中.如果是这样，我们之前已经看过这段文字，所以我们删除了链接.否则，这是我们第一次看到的链接文本.我们将其添加到集合中，以便删除具有相同文本的任何进一步链接.

seen is an object which maps any previously seen text to true. It functions as a set containing all previously seen texts. The line if (seen[txt]) checks to see if the text is in the set. If so, we've seen this text before, so we remove the link. Otherwise, this is a link text we see for the first time. We add it to the set so that any further links with the same text will be removed.

表示集合的另一种方法是使用包含所有值的数组.但是，这会使其速度变慢，因为要查看数组中是否有值，我们每次都需要扫描整个数组.相比之下，使用 seen[txt] 在对象中查找键非常快.

An alternative way to represent a set is to use an array containing all values. However, this would make it much slower since to see if a value is in the array we'd need to scan the entire array each time. Looking up a key in an object using seen[txt] is very fast in comparison.

这篇关于JQuery:删除重复元素?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！