外部内联函数会发生什么? [英] What happens with an extern inline function?
问题描述
如果我将 .h 文件中的函数定义为
extern int returnaint(void);
在相关的.c文件中定义为
inline int returnaint(void) {返回 1;}
并将标题包含在另一个 .c 文件中并使用该功能?当我单独编译这些东西,为每个 .c 文件创建一个目标文件然后链接它们时,是否包含内联函数,或者会发生什么?
我知道编译器可以忽略inline
,但是如果在这种情况下不忽略呢?
在 .c
文件的函数定义中添加 inline
是多余的.p>
.c
文件的编译单元看到一个extern
声明(没有inline
)和一个inline代码>定义.因此它会在目标文件中发出函数的符号.
所有其他编译单元只能看到
extern
声明,因此如果您将最终可执行文件与其他.o
文件.
事实上,你只是用错了方法.此功能旨在用于您在 .h
文件中具有 inline
定义,对所有人可见.该函数的定义仅作为符号的声明,就像 extern
一样,但没有定义它.
extern
声明仅在一个 .c
文件(编译单元)中,然后确保在那里定义符号.
术语有点混乱,inline
definition 充当符号的声明,而 extern
declaration 作为它的定义
What happens if I define the function in my .h file as
extern int returnaint(void);
define it in the related .c file as
inline int returnaint(void) {
return 1;
}
and include the header in another .c file and use the function? When I compile the things seperatly, creating a object file for each .c file and then link them, is the inlined function included, or what happens?
I know the compiler can ignore inline
, but what if it does not ignore it in this case?
Having added the inline
to the function definition in the .c
file is just superfluous.
Your compilation unit of the
.c
file sees anextern
declaration (withoutinline
) and aninline
definition. Thus it emits the symbol for the function in the object file.All other compilation units only see an
extern
declaration, and so they can use the function without problems, if you link your final executable with the other.o
file.
In fact, you just have it the wrong way around. This feature is meant to be used that you have the inline
defintion in the .h
file, visible to everybody. This definition of the function only acts as a declaration of the symbol, just as extern
would, but doesn't define it.
An extern
declaration in just one .c
file (compilation unit) then ensures such that the symbol is defined, there.
The terminology is a bit confusing, the inline
definition acting as declaration of the symbol, and the extern
declaration acting as definition of it
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