Gulp 将多个 js 文件缩小为一个 [英] Gulp minify multiple js files to one

问题描述

我是 Gulp 的新手，想知道如何将我的集合缩小(连接)到单个文件而不是单独的每个文件.

I am new to Gulp and wondering how can I minify (concatinate) my collection to single file instead of every file separately.

var gulp = require('gulp');
var uglify = require('gulp-uglify');

gulp.task('minify', function () {
   gulp.src([
        'content/plugins/jquery/jquery-2.1.1.js',
        'content/plugins/jquery/jquery-ui.js',
        'content/js/client.js'])
      .pipe(uglify())
      .pipe(gulp.dest('content/js/client.min.js')) // It will create folder client.min.js
});

gulp.task('default', ['minify']);

如您所见，我正在尝试缩小 3 个 javascript 文件，然后将它们输出到一个 client.min.js 中.有可能吗?

As you can see I'm trying to minify 3 javascript files and then output them into one client.min.js. Is it possible?

推荐答案

这个插件将帮助 gulp-concat.

用法:

var concat = require('gulp-concat');

gulp.task('scripts', function() {
  gulp.src(['./lib/file3.js', './lib/file1.js', './lib/file2.js'])
    .pipe(concat('all.js'))
    .pipe(uglify())
    .pipe(gulp.dest('./dist/'))
});

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