如何在 Java 中将 char 转换为 int? [英] How can I convert a char to int in Java?

问题描述

(我是 Java 编程新手)

(I'm new at Java programming)

例如:

char x = '9';

我需要得到撇号中的数字，即数字 9 本身.我尝试执行以下操作，

and I need to get the number in the apostrophes, the digit 9 itself. I tried to do the following,

char x = 9;
int y = (int)(x);

但是没有用.

那么我应该怎么做才能得到撇号中的数字呢?

So what should I do to get the digit in the apostrophes?

推荐答案

排列ASCII表，使得字符'9'的值比'的值大90';字符'8'的值比'0'的值大8；等等.

The ASCII table is arranged so that the value of the character '9' is nine greater than the value of '0'; the value of the character '8' is eight greater than the value of '0'; and so on.

所以你可以通过减去'0'得到一个十进制数字char的int值.

So you can get the int value of a decimal digit char by subtracting '0'.

char x = '9';
int y = x - '0'; // gives the int value 9

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