如何检查 C 字符串中是否存在单个字符? [英] How can I check if a single char exists in a C string?
问题描述
我想检查单个字符是否在 C 字符串中.字符是 '|'
用于Linux中的管道(实际上我也想检查 '<'
, '>'
, '>>'
, '&'
).
I want to check if a single char is in a C string. The character is the '|'
used for pipelines in Linux (Actually, I also want to check for '<'
, '>'
, '>>'
, '&'
).
在 Java 中我可以这样做:
In Java I can do this:
String.indexOf()
但是如何在 C 中做到这一点,而不循环整个字符串(char*
字符串)?
But how can I do this in C, without looping through the whole string (a char*
string)?
推荐答案
如果需要搜索字符可以使用strchr
函数,如下:
If you need to search for a character you can use the strchr
function, like this:
char* pPosition = strchr(pText, '|');
如果未找到给定字符,则
pPosition
将为 NULL
.例如:
pPosition
will be NULL
if the given character has not been found. For example:
puts(strchr("field1|field2", '|'));
将输出:|field2".请注意,strchr
将执行 forward 搜索,要搜索 backward 您可以使用 strrchr
.现在想象一下(只是提供一个例子)你有一个这样的字符串:变量:值|条件".您可以使用以下方法提取 value 字段:
Will output: "|field2". Note that strchr
will perform a forward search, to search backward you can use the strrchr
. Now imagine (just to provide an example) that you have a string like this: "variable:value|condition". You can extract the value field with:
char* pValue = strrchr(strchr(pExpression, '|'), ':') + 1;
如果您想要的是字符串中字符的 index,请查看 这篇文章在这里.您可能还需要 IndexOfAny()
之类的东西,这里关于 SO 的另一篇文章使用 strnspn
.
If what you want is the index of the character inside the string take a look to this post here on SO. You may need something like IndexOfAny()
too, here another post on SO that uses strnspn
for this.
如果您要查找字符串,则可以使用 strstr
函数,如下所示:
Instead if you're looking for a string you can use the strstr
function, like this:
char* pPosition = strstr(pText, "text to find");
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