平台 localtime()/gmtime() 函数的时间戳超出范围 [英] Timestamp out of range for platform localtime()/gmtime() function

问题描述

我试试:

ts = -216345600000
datetime.datetime.fromtimestamp(ts/1000)

ValueError:平台 localtime()/gmtime() 函数的时间戳超出范围

我检查 epochconverter 值:-216345600 其返回 GMT:星期六，1963 年 2 月 23 日 00:00:格林威治标准时间 00

I check on epochconverter value : -216345600 its return GMT: Sat, 23 Feb 1963 00:00:00 GMT

如何得到正确的结果?

推荐答案

对于许多值，比如过去或未来太远，只需将时间戳提供给 fromtimestamp() 就会报错超出范围错误.但是，您可以使用 timedelta() 相对于时代.

For many values, like too far in the past or the future, just feeding the timestamp to fromtimestamp() will complain with an out of range error. However, you can calculate the date using timedelta() relative from the epoch.

>>> from datetime import datetime, timedelta
>>> date = datetime(1970, 1, 1) + timedelta(seconds=-216345600)
>>> date
datetime.datetime(1963, 2, 23, 0, 0)
>>> date.strftime('%a, %d %b %Y %H:%M:%S GMT')
'Sat, 23 Feb 1963 00:00:00 GMT'

但是，请注意，您不能使用它来回到恐龙时代，因为 datetime() 仍然有它可以支持的最小值和最大值.

However, do note that you can't use this to go back to the dinosaur era, since datetime() still has a min and max value it can support.

>>> datetime(1970, 1, 1) + timedelta(seconds=-62135596800)
datetime.datetime(1, 1, 1, 0, 0)
>>> datetime(1970, 1, 1) + timedelta(seconds=253402300799)
datetime.datetime(9999, 12, 31, 23, 59, 59)
>>> datetime(1970, 1, 1) + timedelta(seconds=253402300800)

Traceback (most recent call last):
  File "<pyshell#157>", line 1, in <module>
    datetime(1970, 1, 1) + timedelta(seconds=253402300800)
OverflowError: date value out of range

timedelta() 也有其局限性，但以时代为参考点，我们甚至还没有达到.

timedelta() has its limits as well, but with the epoch as a reference point, we haven't come even near reaching them.

>>> timedelta(microseconds=1000000000*86400*10000-1)
datetime.timedelta(9999999, 86399, 999999)

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