Javascript比较两个日期以获得差异 [英] Javascript compare two dates to get a difference

问题描述

我正在尝试比较两个不同的日期，以查看输入的日期是否在今天日期的 7 天之后.我做了一些谷歌搜索并想出了这个:

I am trying to compare two different dates to see if the date inputted is after 7 days of todays date. I have done a bit of googling and come up with this:

function val_date(input){
    var date = new Date(input);
    date = date.getTime() / 1000;
    var timestamp = new Date().getTime() + (7 * 24 * 60 * 60 * 1000)
    window.alert("Date: "+date + " = N_Date: "+timestamp);
    if(timestamp > date || timestamp === date){
        // The selected time is less than 7 days from now
        return false;
    }
    else if(timestamp < date){
    // The selected time is more than 7 days from now
        return true;
    }
    else{
    // -Exact- same timestamps.
        return false;
    }
}

我正在使用提醒，以便我可以检查我的进度以确保日期不同.警报的输出只是说:

I am using an alert so that I can check my progress to make sure the dates are different. The output of the alert just says:

日期:NaN = N_Date = 13255772630(<- 或类似的东西).

Date: NaN = N_Date = 13255772630 (<- or something like that).

我在这里做错了吗?
不确定是否有帮助，但我的日期格式是 DD-MM-YYYY

推荐答案

如果你在比较日期并且不想包含时间，你可以使用类似的东西:

If you are comparing dates and don't want to include time, you can use something like:

// dateString is format DD-MM-YYYY
function isMoreThan7DaysHence(dateString) {

    // Turn string into a date object at 00:00:00
    var t = dateString.split('-');
    var d0 = new Date(t[2], --t[1], t[0]);

    // Create a date for 7 days hence at 00:00:00
    var d1 = new Date();
    d1.setHours(0, 0, 0, 0);
    d1.setDate(d1.getDate() + 7);

    return d0 >= d1;
}

请注意，今天日期的小时数必须归零.

Note that the hours for today's date must be zeroed.

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