将坐标从一个三角形转移到另一个三角形 [英] Transfer coordinates from one triangle to another triangle

问题描述

我有两个三角形，可以是任意大小.问题是，我如何将坐标从一个三角形转移到另一个三角形?我知道坐标系中的三角形位置，是的，它们都在一个系统中.

I have two triangles , which can be in any sizes. The problem is that, how I can transfer coordinates from one triangle to another? I know both of triangle position in coordinate system and yes, they both are in one system.

基本上，我在三角形 1 中有点，我需要在三角形 2 中转移它.

Basically, i have point in triangle1 and I need to transfer it in triangle2.

看了一些帖子，我发现我可以使用仿射变换矩阵进行计算，但是我不明白如何使用仿射变换矩阵来解决这个问题.

Reading some posts, I found out that I could be calculated using affine transformation matrix, but I didn't undestand how to solve this with affine transformation matrix.

感谢您的帮助.

推荐答案

让你拥有未知的仿射变换矩阵

Let you have unknown affine transformation matrix

   | a c e |
M =| b d f |
   | 0 0 1 |

第一个三角形顶点是(xa1, ya1), (xa2, ya2), (xa3, ya3)，第二个三角形顶点坐标是(xb1, yb1), (xb2, yb2), (xb3, yb3).

The first triangle vertices are (xa1, ya1), (xa2, ya2), (xa3, ya3), and the second triangle vertices have coordinates (xb1, yb1), (xb2, yb2), (xb3, yb3).

那么将第一个三角形顶点变换到第二个顶点的仿射变换M是:

Then affine transformation M that transforms the first triangle vertices to the second one vertices is:

M * A = B

在哪里

   | xa1 xa2 xa3 |
A =| ya1 ya2 ya3 |
   |  1   1   1  |

   | xb1 xb2 xb3 |
B =| yb1 yb2 yb3 |
   |  1   1   1  |

要找到未知的M，我们可以将表达式两边乘以A矩阵的逆

To find unknown M, we can multiply both sides of the expression by inverse of A matrix

M * A * Inv(A) = B * Inv(A)
M = B * Inv(A)

A的反转比较简单(由Maple计算，可能由于我的拼写错误而包含错误):

Inversion of A is rather simple (calculated by Maple, may contain errors due to my typos):

| (ya2-ya3)    -(xa2-xa3)    (xa2*ya3-xa3*ya2)  |
| -(-ya3+ya1)  (-xa3+xa1)    -(xa1*ya3-ya1*xa3) | * 1/Det
| (-ya2+ya1)   -(-xa2+xa1)   (xa1*ya2-ya1*xa2)  |

决定值在哪里

Det = xa2*ya3-xa3*ya2-ya1*xa2+ya1*xa3+xa1*ya2-xa1*ya3

因此您可以找到所需变换的仿射矩阵并将其应用于坐标(乘以 M 和 (x,y,1) 列矩阵)

So you can find affine matrix for needed transformation and apply it to coordinates (multiply M and (x,y,1) column matrix)

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