Android:操作方法:将当前位置标记到地图中(静止图像) - 添加了源代码、测试用例、实际、预期输出 [英] Android: How To: mark the current location into a map (still image) - SOURCE CODE,TESTCASE,ACTUAL,EXPECTED OUTPUT ADDED

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问题描述

我创建了另一个问题(来介绍如何使用 OSMDroid (这是最好的开源替代品)和 another post with ArcGIS(Android 的免费地图控制器, 商业地图图块;这个控制器的一切都很棒,但在我看来,它对于论文项目来说太过分了).

所以,这里重现的步骤是:

  • 将大文件分成更小的部分
  • 找到大图像边缘的确切坐标,以准确了解如何命名图块(地图控制器通过名称查找覆盖部分视口所需的图块)
  • 使用您的图像实现离线磁贴提供程序

位置提供者

在我看来,这是最难的部分.您将如何准确地找到设备在建筑物中的确切位置?GPS可以在一定程度上有所帮助,但无论如何它在建筑物中并不精确.ArcGIS 为您提供了一个非常好的内置位置提供程序,在任何其他解决方案上您都必须自己实现它.一旦您设法克服了这个问题,您还可以使用位置提供商提供的高度在楼层之间自动切换.

路由

用 OSMDroid(好吧,也可以用 ArcGIS)来表示路由线是一块巧克力蛋糕:创建一个转折点数组,从一个点画一条线到另一个点,然后将该线放在地图上.困难的部分是创建一个路由算法,祝你好运!

I have created another question (How to display a map (still image file) with a moving current location)

But it contains 2 (two) questions, so i need to segregate it.

I am trying to create a prototype that could guide a person to his destination place.

  • place is a wide building with several floors.
  • i can obtain/retrieve the maps (still images). e.g. current:1F destination:5F; so I can get the still images of 1st,2nd...5th floors (5 image files).

Scenario:

  1. start the application
  2. input the current location (or may automatically set using current location) & destination
  3. click the search route button to search the maps to use (still images) & mark the current location & destination
  4. update the current location upon moving/going to destination

Problem: I can get the current location coordinate via WiFi/cell tower/ip address but don't know how to put it into still image to mark the current location.

Would you share the concepts/ideas or include the code snippets. Big Help with my thesis.

Any guidance on the right direction is appreciated.


UPDATE

Actual Example with Actual,Expected Output,Test Case (parcel of codes here has gotten from mapsforge)

MercatorProjectionClass.java

/**
 * A performance optimized implementation of the spherical Mercator projection.
 */
class MercatorProjectionClass {
    /**
     * Width and height of a map tile in pixel.
     */
    static final int TILE_SIZE = 256;

    /**
     * Converts a latitude coordinate (in degrees) to a pixel Y coordinate at a certain zoom level.
     * 
     * @param latitude
     *            the latitude coordinate that should be converted.
     * @param zoom
     *            the zoom level at which the coordinate should be converted.
     * @return the pixel Y coordinate of the latitude value.
     */
    static double latitudeToPixelY(double latitude, byte zoom) {
        double sinLatitude = Math.sin(latitude * (Math.PI / 180));
        return (0.5 - Math.log((1 + sinLatitude) / (1 - sinLatitude)) / (4 * Math.PI))
                * ((long) TILE_SIZE << zoom);
    }

    /**
     * Converts a latitude coordinate (in degrees) to a tile Y number at a certain zoom level.
     * 
     * @param latitude
     *            the latitude coordinate that should be converted.
     * @param zoom
     *            the zoom level at which the coordinate should be converted.
     * @return the tile Y number of the latitude value.
     */
    static long latitudeToTileY(double latitude, byte zoom) {
        return pixelYToTileY(latitudeToPixelY(latitude, zoom), zoom);
    }

    /**
     * Converts a longitude coordinate (in degrees) to a pixel X coordinate at a certain zoom level.
     * 
     * @param longitude
     *            the longitude coordinate that should be converted.
     * @param zoom
     *            the zoom level at which the coordinate should be converted.
     * @return the pixel X coordinate of the longitude value.
     */
    static double longitudeToPixelX(double longitude, byte zoom) {
        return (longitude + 180) / 360 * ((long) TILE_SIZE << zoom);
    }

    /**
     * Converts a longitude coordinate (in degrees) to the tile X number at a certain zoom level.
     * 
     * @param longitude
     *            the longitude coordinate that should be converted.
     * @param zoom
     *            the zoom level at which the coordinate should be converted.
     * @return the tile X number of the longitude value.
     */
    static long longitudeToTileX(double longitude, byte zoom) {
        return pixelXToTileX(longitudeToPixelX(longitude, zoom), zoom);
    }

    /**
     * Converts a pixel X coordinate at a certain zoom level to a longitude coordinate.
     * 
     * @param pixelX
     *            the pixel X coordinate that should be converted.
     * @param zoom
     *            the zoom level at which the coordinate should be converted.
     * @return the longitude value of the pixel X coordinate.
     */
    static double pixelXToLongitude(double pixelX, byte zoom) {
        return 360 * ((pixelX / ((long) TILE_SIZE << zoom)) - 0.5);
    }

    /**
     * Converts a pixel X coordinate to the tile X number.
     * 
     * @param pixelX
     *            the pixel X coordinate that should be converted.
     * @param zoom
     *            the zoom level at which the coordinate should be converted.
     * @return the tile X number.
     */
    static long pixelXToTileX(double pixelX, byte zoom) {
        return (long) Math.min(Math.max(pixelX / TILE_SIZE, 0), Math.pow(2, zoom) - 1);
    }

    /**
     * Converts a pixel Y coordinate at a certain zoom level to a latitude coordinate.
     * 
     * @param pixelY
     *            the pixel Y coordinate that should be converted.
     * @param zoom
     *            the zoom level at which the coordinate should be converted.
     * @return the latitude value of the pixel Y coordinate.
     */
    static double pixelYToLatitude(double pixelY, byte zoom) {
        double y = 0.5 - (pixelY / ((long) TILE_SIZE << zoom));
        return 90 - 360 * Math.atan(Math.exp(-y * (2 * Math.PI))) / Math.PI;
    }

    /**
     * Converts a pixel Y coordinate to the tile Y number.
     * 
     * @param pixelY
     *            the pixel Y coordinate that should be converted.
     * @param zoom
     *            the zoom level at which the coordinate should be converted.
     * @return the tile Y number.
     */
    static long pixelYToTileY(double pixelY, byte zoom) {
        return (long) Math.min(Math.max(pixelY / TILE_SIZE, 0), Math.pow(2, zoom) - 1);
    }

    private static final byte ZOOM_LEVEL = 14;

    /**
     * @param args
     */
    public static void main(String[] args) {
        // Pixel Coordinate of Chicago,IL
        double pixel_y = 1559345;
        double pixel_x = 1075954;
        // Lat Lng of Chicago,IL
        double lat_y = 41.850033;
        double lng_x = -87.65005229999997; 

        testPixelXYToLatitude(pixel_y, pixel_x, lat_y, lng_x);
        testLatLngToPixelXY(pixel_y, pixel_x, lat_y, lng_x);
    }

    private static void testPixelXYToLatitude(
            double pixel_y, double pixel_x, 
            double lat_y, double lng_x) {

        double actual_lat_y = MercatorProjectionClass.pixelYToLatitude(pixel_y, ZOOM_LEVEL);
        double actual_lng_x = MercatorProjectionClass.pixelXToLongitude(pixel_x, ZOOM_LEVEL);

        String expectedstr_lat_y = Double.toString(lat_y).substring(0, 5);
        String expectedstr_lng_x = Double.toString(lng_x).substring(0, 6);

        String actualstr_lat_y = Double.toString(actual_lat_y).substring(0, 5);
        String actualstr_lng_x = Double.toString(actual_lng_x).substring(0, 6);

        String result = (actualstr_lat_y.equals(expectedstr_lat_y) && actualstr_lng_x.equals(expectedstr_lng_x))?"PASSED":"FAILED"; 
        System.out.println("PixelXYToLatitude test result:" + result);
    }

    private static void testLatLngToPixelXY(
            double pixel_y, double pixel_x, 
            double lat_y, double lng_x) {

        double actual_pixel_y = MercatorProjectionClass.latitudeToPixelY(lat_y, ZOOM_LEVEL);
        double actual_pixel_x = MercatorProjectionClass.longitudeToPixelX(lng_x, ZOOM_LEVEL);

        String expectedstr_pixel_y = Integer.toString((Double.valueOf(pixel_y).intValue()));
        String expectedstr_pixel_x = Integer.toString((Double.valueOf(pixel_x).intValue()));

        String actualstr_pixel_y = Integer.toString(Double.valueOf(actual_pixel_y).intValue());
        String actualstr_pixel_x = Integer.toString(Double.valueOf(actual_pixel_x).intValue());

        String result = (actualstr_pixel_y.equals(expectedstr_pixel_y) && actualstr_pixel_x.equals(expectedstr_pixel_x))?"PASSED":"FAILED"; 
        System.out.println("LatLngToPixelXY test result:" + result);
    }
}

Output of the above code:

  • PixelXYToLatitude test result:PASSED
  • LatLngToPixelXY test result:PASSED

I have already the projection class to convert LatLng to Pixel. My Problem now is on how to mark into still image of a given LatLng using the above class.

Here's my still image (Chicago,IL):

I want to put a mark (here's the example but later on need to change the balloon to smaller pointer)

解决方案

From what I understood, you are facing a few problems here.

  • Use a map controller with offline tiles

  • Mark the current location on the map

  • Route the user from point A to point B


Map controller

Basically, the location providers on Android will be feeding your application with some global positioning coordinates (longitude and latitude) and you want to put a background behind it so that the user has a visual on his location. Your idea to put a still image there is right, but a correction I would suggest (and this is the way it works on every commercial, or non-commercial, product) is to split the large images into smaller parts, so that the map controller wouldn't have to load a large image into memory. 512 x 512 sounds like a reasonable size (Google maps uses 256 x 256). These chunks of larger images are called tiles.

With Google maps it's impossible to use offline tiles. I've written a post on how to do that for Google maps with OSMDroid (this is the best open source alternative) and another post with ArcGIS (free map controller for Android, commercial map tiles; everything is awesome with this controller but in my opinion it's too loaded for a thesis project).

So, the steps to reproduce here are:

  • chunk big files into smaller parts
  • find the exact coordinates of the edges of your big images to know exactly how to name the tiles (map controllers find tiles required to cover a portion of the viewport by names)
  • implement an offline tile provider with your images

Location provider

This, in my opinion is the hardest part. How exactly are you going to find the exact position of a device in a building? GPS can be of a help to a certain extent, but it can't be precise in a building anyway. ArcGIS provides you with a very nice built-in location provider, on any other solution you'll have to implement it on your own. As soon as you manage to overcome this problem you can also use the altitude provided by the location providers to switch between the floors automatically.

Routing

To represent a routing line with OSMDroid (well, with ArcGIS as well) is a piece of chocolate cake: create an array of turn points, draw a line from one point to another and put that line on the map. The hard part is to create a routing algorithm, good luck with that!

这篇关于Android:操作方法:将当前位置标记到地图中(静止图像) - 添加了源代码、测试用例、实际、预期输出的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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