使用 .NET XmlSerializer 反序列化时使用多个命名空间 [英] Use multiple namespaces when deserializing with .NET XmlSerializer

问题描述

我正在尝试使用两个命名空间来反序列化 XML，就像这样

I'm trying to deserialize XML with two namespaces, like this

<records xmlns="http://www.foo.com/xml/records/1.1">
    <record xmlns="http://www.foo.com/xml/record/1.1">

有时是旧版本

<records xmlns="http://www.foo.com/xml/records/1.1">
    <record xmlns="http://www.foo.com/xml/record/1.0">

我的 Records.cs 类有

My Records.cs class has

[XmlRoot(ElementName = "records", Namespace = "http://www.foo.com/xml/records/1.1")]
public class Records
{
    [System.Xml.Serialization.XmlElementAttribute("record")]
    public List<Record> Records { get; set; }
}

我希望记录列表能够包含 1.0 版或 1.1 版记录

I want the Records list to be able to contain either a version 1.0 or version 1.1 Record

/// <remarks/>
[XmlRoot(IsNullable = false, ElementName = "record", Namespace = "http://www.foo.com/xml/record/1.0")]
public partial class Record
{


    /// <remarks/>

    public Record()
    {

    }
}

/// <remarks/>
[XmlRoot(IsNullable = false, ElementName = "record", Namespace = "http://www.foo.com/xml/record/1.1")]
public partial class Record11 : Record
{
    /// <remarks/>
    public Record11()
    {
    }
}

所以我假设子类化记录会起作用.

so I assumed subclassing the record would work.

反序列化时出现反射异常，异常指向 XmlChoiceIdentifier 属性.但是，这似乎与枚举有关.

I get a Reflection exception when deserializing and the exception points me to the XmlChoiceIdentifier attribute. However, that seems related to enums.

任何人都知道如何做我想做的事(支持反序列化同一架构的多个版本?)

Anyone know how to do what I want to do (support deserializing multiple versions of the same schema?)

谢谢.

推荐答案

[XmlRoot] 在您的示例中的 Record 和 Record11 属性将被忽略.只有当元素是树中的根时，它们才有意义.你需要做的是:

[XmlRoot] attributes on both Record and Record11 in your example will be ignored. They only have meaning when element is a root in the tree. What you rather need to do is this:

[XmlRoot(ElementName = "records",
         Namespace = "http://www.foo.com/xml/records/1.1")]
public class Records
{
    [XmlElement(Type = typeof(Record),
                ElementName = "record",
                Namespace = "http://www.foo.com/xml/records/1.0")]
    [XmlElement(Type = typeof(Record11),
                ElementName = "record",
                Namespace = "http://www.foo.com/xml/records/1.1")]
    public List<Record> Records { get; set; }
}

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