教义 - 来自的子查询 [英] Doctrine - subquery in from

问题描述

我在 MySQL 中有一个查询:

I have a query in MySQL:

SELECT * FROM (
    SELECT COUNT(*) AS count, t.name AS name
    FROM tag t
    INNER JOIN video_has_tag v USING (idTag)
    GROUP BY v.idTag
    ORDER BY count DESC
    LIMIT 10
) as tags ORDER BY name

我想用教义来写这个.我怎么能这样做?我写道:

and I want to write this in doctrine. How I can do that? I wrote:

Doctrine_Query::create()
        ->select('COUNT(t.idtag) as count, t.name')
        ->from('Tag t')
        ->innerJoin('t.VideoHasTag v')
        ->groupBy('v.idTag')
        ->orderBy('count DESC, t.name')
        ->limit(30)
        ->execute();

但我不能把它放在从"中按名称排序.

But I can't put it in "from" to sort by name.

推荐答案

这是一个答案:

$q = new Doctrine_RawSql();
$q->addComponent('t', 'Tag')
    ->select('{t.name}, {t.count}')
    ->from('(SELECT COUNT(*) as count, t.name,t.idtag
        FROM Tag t
            INNER JOIN Video_Has_Tag v USING(idTag)
        GROUP BY v.idTag
        ORDER BY count DESC
        LIMIT 50) t')
    ->orderBy('name');

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