是否可以运行任务“symfony dictionary build --all"?只有一张桌子? [英] Is it possible to run the task "symfony doctrine build --all" on only one table?

问题描述

如果我运行以下任务，它会构建所有内容并清除数据库:

If I run the folowing task, it builds everything and wipes out the database:

php symfony doctrine build --all

我希望这个任务只为我放入 schema.yml 的新表运行

I would like this task to run only for the new table that I've put in schema.yml

有可能吗?

推荐答案

我认为你应该为此使用迁移.

I think you should use migration for that.

首先，您需要恢复初始状态(当模式、模型和数据库同步时).从 schema.yml 中删除您的更改，重建您的模型 php symfony 学说:build --all-classes 并导入原始​​数据库.

First, you need to restore the initial state (when schema, model and db are in sync). Remove your changes form schema.yml rebuild your model php symfony doctrine:build --all-classes and import the original database.

然后在 schema.yml 中进行更改并运行以下命令:

After that make your changes in schema.yml and run these commands:

php symfony doctrine:generate-migrations-diff
php symfony doctrine:migrate
php symfony doctrine:build --all-classes

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