如何在不迭代的情况下获取给定 LinkedHashSet 元素的索引? [英] How to obtain index of a given LinkedHashSet element without iteration?
问题描述
有可能吗?
说你有
private Set<String> names = new LinkedHashSet<String>();
和 Strings
是Mike"、John"、Karen".
and Strings
are "Mike", "John", "Karen".
是否有可能在不迭代的情况下得到1"来返回John"的索引是多少?
Is it possible to get "1" in return to "what's the index of "John" without iteration?
以下工作正常..这个问题我想知道是否有更好的方法
The following works fine .. with this question i wonder if there is a better way
for (String s : names) {
++i;
if (s.equals(someRandomInputString)) {
break;
}
}
推荐答案
Set
interface 没有类似 indexOf()
方法.您确实需要对其进行迭代或使用 List
接口 而是提供 indexOf()
方法.
The Set
interface doesn't have something like as an indexOf()
method. You'd really need to iterate over it or to use the List
interface instead which offers an indexOf()
method.
如果您愿意,将 Set
转换为 List
非常简单,只需通过构造函数传递 Set
List
的实现.例如
If you would like to, converting Set
to List
is pretty trivial, it should be a matter of passing the Set
through the constructor of the List
implementation. E.g.
List<String> nameList = new ArrayList<String>(nameSet);
// ...
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