如何在 Arduino 上传输字符串? [英] How to transmit a String on Arduino?
问题描述
我想要 2 个 Arduinos Leonardo 进行通信,例如发送一个字符串,所以我必须使用 Serial1
通过引脚 0 (RX) 和 1 (TX) 上的 RS232 进行通信.
I want 2 Arduinos Leonardo to communicate, send a string for instance, so I have to use Serial1
to communicate via RS232 on pins 0 (RX) and 1 (TX).
我需要在该引脚中写入二进制数据,问题是如何使用 Serial1.write
发送字符串.Serial1.print
可以正常工作,但我认为它不能满足我的要求.有什么建议吗?
I need to write binary data in that pins, the problem is how can I send a String using Serial1.write
. Serial1.print
works without errors but I think it does not do what I want. Any suggestion?
void setup() {
Serial.begin(9600);
Serial1.begin(9600);
while (!Serial); // while not open, do nothing. Needed for Leonardo only
}
void loop() {
String outMessage = ""; // String to hold input
while (Serial.available() > 0) { // check if at least one char is available
char inChar = Serial.read();
outMessage.concat(inChar); // add Chars to outMessage (concatenate)
}
if (outMessage != "") {
Serial.println("Sent: " + outMessage); // see in Serial Monitor
Serial1.write(outMessage); // Send to the other Arduino
}
}
这一行 Serial1.write(outMessage);
给了我错误
"没有匹配的函数调用'HardwareSerial::write(String&)'
"
推荐答案
你正在使用 String 对象(Wiring/C++).该函数使用 C 字符串:Serial.write(char*).要将其转换为 C 字符串,请使用 toCharArray() 方法.
You're using the String object(Wiring/C++). The function is using C strings: Serial.write(char*). To turn it into a C string, you use the toCharArray() method.
char* cString = (char*) malloc(sizeof(char)*(outMessage.length() + 1);
outMessage.stoCharArray(cString, outMessage.length() + 1);
Serial1.write(cString);
如果我们不使用 malloc 为 C 字符串分配内存,就会出错.以下代码将崩溃.
If we do not allocate the memory for our C string with malloc, we will get a fault. The following code WILL crash.
void setup() {
Serial.begin(9600);
String myString = "This is some new text";
char* buf;
Serial.println("Using toCharArray");
myString.toCharArray(buf, myString.length()+1); // **CRASH** buf is not allocated!
Serial.println(buf);
}
void loop() {
// put your main code here, to run repeatedly:
}
在串行监视器中,我们将得到的唯一消息是:使用 toCharArray.此时执行停止.现在,如果我们纠正问题并使用 malloc() 为我们的缓冲区分配内存,并在完成后使用 free() ......
In the Serial Monitor the only message we will get is: Using toCharArray. At that point execution stops. Now if we correct the problem and use malloc() to allocate memory for our buffer and also use free() when done....
void setup() {
Serial.begin(9600);
String myString = "This is some new text";
char* buf = (char*) malloc(sizeof(char)*myString.length()+1);
Serial.println("Using toCharArray");
myString.toCharArray(buf, myString.length()+1);
Serial.println(buf);
Serial.println("Freeing the memory");
free(buf);
Serial.println("No leaking!");
}
void loop() {
// put your main code here, to run repeatedly:
}
我们在串行监视器中看到的输出是:使用 toCharArray这是一些新的文本释放内存没有泄漏!
The output we see in the Serial Monitor is: Using toCharArray This is some new text Freeing the memory No leaking!
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