C execv() 函数是否终止子进程? [英] Does the C execv() function terminate the child proccess?

问题描述

这是我的代码的细分.

我有一个程序可以派生一个孩子(并将孩子的 pid 注册到一个文件中)，然后做自己的事情.孩子成为程序员用 argv 有尊严的任何程序.当子进程完成执行时，它会向父进程发送一个信号(使用 SIGUSR1)，以便父进程知道从文件中删除子进程.父级应该停止一秒钟，通过更新其表来确认已删除的条目，然后从中断的地方继续.

pid = fork();开关(PID){情况1:{退出(1)；}案例0:{(*table[numP-1]).pid = getpid();//全局存储pid添加();//将表格保存到文本文件中自由(表)；//释放表execv(argv[3], &argv[4]);//使用argv执行新程序printf("执行完毕
");德尔(getpid())；//从文件中删除pid刷新请求()；//发送SIGUSR1给父母返回0；}默认:{...//做自己的事}}

问题是 after execv 成功启动并完成(返回 0 之前的 printf 语句让我知道)，我没有看到 switch 语句中的其余命令正在执行.我想知道 execv 中是否有一个 ^C 命令，它在完成时会杀死孩子，因此永远不会完成其余的命令.我查看了手册页，但没有发现任何关于该主题的有用信息.

谢谢！

解决方案

execv 用新进程替换当前进程.为了产生一个新进程，您可以使用例如system()、popen() 或 fork() 和 exec()

Heres a breakdown of my code.

I have a program that forks a child (and registers the child's pid in a file) and then does its own thing. The child becomes any program the programmer has dignified with argv. When the child is finished executing, it sends a signal (using SIGUSR1) back to the parent processes so the parent knows to remove the child from the file. The parent should stop a second, acknowledge the deleted entry by updating its table, and continue where it left off.

pid = fork();
switch(pid){
case -1:{
    exit(1);
}

case 0 :{
    (*table[numP-1]).pid = getpid(); //Global that stores pids
    add();                             //saves table into a text file 
    freeT(table);                  //Frees table 
    execv(argv[3], &argv[4]);          //Executes new program with argv 
    printf("finished execution
");  
    del(getpid());                     //Erases pid from file 
    refreshReq();                      //Sends SIGUSR1 to parent
    return 0;
}
default:{
    ... //Does its own thing
}
}

The problem is that the after execv successfully starts and finishes (A printf statement before the return 0 lets me know), I do not see the rest of the commands in the switch statement being executed. I am wondering if the execv has like a ^C command in it which kills the child when it finishes and thus never finishes the rest of the commands. I looked into the man pages but did not find anything useful on the subject.

Thanks!

解决方案

execv replaces the current process with a new one. In order to spawn a new process, you can use e.g. system(), popen(), or a combination of fork() and exec()

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