在 jqgrid 中验证失败时突出显示错误单元格或输入 [英] highlight error cell or input when validation fails in jqgrid

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本文介绍了在 jqgrid 中验证失败时突出显示错误单元格或输入的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在使用 jqgrid 内联编辑并使用编辑规则在网格中进行验证.我想为验证失败的输入添加类以突出显示错误(例如:ui-state-error).我可以使用此设置类以突出显示错误

I am using jqgrid inline editing with validation in grid using edit rules . i want to add class to highlight errors(eg: ui-state-error) for the input which fails in validation . i can set class to highlight error using this

jQuery('#'+grid_id).jqGrid('setCell',row_id,errfields[a],'','ui-state-error',{color: 'blue'});

但是当内置验证失败时,它在 jqgrid 中不起作用.如何突出显示验证错误触发的单元格/输入.

But it is not working in jqgrid when inbuilt validation fails . How do i highlight the validation error triggered cell/input .

推荐答案

演示 展示了如何解决问题:

The demo shows how the probelm can be solved:

在演示中,金额"、税收"和总计"列将使用以下验证规则进行验证:

In the demo the columns "Amount", "Tax" and "Total" will be validated with the following validation rule:

editrules:{required:true,number:true}

在出现任何验证错误时,将添加验证失败的第一个输入字段以及其他类ui-state-error".它是标准的 jQuery UI CSS 类.此外,我将焦点设置到输入字段.

On any validation error the first input field where the validation failed dditional class "ui-state-error" will be added. It is the standard jQuery UI CSS class. Addionally I set focus to the input field.

对于实现,我覆盖(链)方法 $.jgrid.checkValues$.jgrid.hideModal 的默认实现.下面是对应的代码:

For the implementation I overwride (chain) the default implementation of the methods $.jgrid.checkValues and $.jgrid.hideModal. Here is the corresponding code:

var grid = $("#list");
grid.jqGrid({
    // define all jqGrid options
});

var originalCheckValues = $.jgrid.checkValues,
    originalHideModal = $.jgrid.hideModal,
    iColWithError = 0;
$.jgrid.checkValues = function(val, valref,g, customobject, nam) {
    var tr,td,
        ret = originalCheckValues.call(this,val, valref,g, customobject, nam);
    if (!ret[0]) {
        tr = g.rows.namedItem(editingRowId);
        if (tr) {
            $(tr).children('td').children('input.editable[type="text"]').removeClass("ui-state-error");
            iColWithError = valref; // save to set later the focus
            //error_td_input_selector = 'tr#'+editingRowId+' > td:nth-child('+(valref+1)+') > input.editable[type="text"]:first';
            td = tr.cells[valref];
            if (td) {
                $(td).find('input.editable[type="text"]').addClass("ui-state-error");
            }
        }
    }
    return ret;
};
$.jgrid.hideModal = function (selector,o) {
    var input, oldOnClose, td,
        tr = grid[0].rows.namedItem(editingRowId);
    if (tr) {
        td = tr.cells[iColWithError];
        if (td) {
            input = $(td).children('input.editable[type="text"]:first');
            if (input.length > 0) {
                oldOnClose = o.onClose;
                o.onClose = function(s) {
                    if ($.isFunction(oldOnClose)) {
                        oldOnClose.call(s);
                    }
                    setTimeout(function(){
                        input.focus();
                    },100);
                };
            }
        }
    }
    originalHideModal.call(this,selector,o);
};

这篇关于在 jqgrid 中验证失败时突出显示错误单元格或输入的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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