C#中的原始布尔大小 [英] Primitive Boolean size in C#

问题描述

C# 中的布尔变量如何存储在内存中?也就是说，它们是否存储为一个字节而其他 7 位被浪费了，或者在数组的情况下，它们是否被分组为 1 字节的布尔块?

How are boolean variables in C# stored in memory? That is, are they stored as a byte and the other 7 bits are wasted, or, in the case of arrays, are they grouped into 1-byte blocks of booleans?

这回答了关于 Java 的相同问题(为什么没有定义 Java 的布尔原始大小?).Java 和 C# 在这方面是否相同?

This answers the same question regarding Java (Why is Java's boolean primitive size not defined?). Are Java and C# the same in this regard?

推荐答案

在 C# 中，当然 bits 默认不打包，因此多个 bool fields 将每个取 1 个字节.您可以使用 BitVector32、BitArray 或简单的按位算术来减少这种开销.作为变量，我似乎记得它们占用 4 个字节(基本上处理为 int = Int32).

In C#, certainly the bits aren't packed by default, so multiple bool fields will each take 1 byte. You can use BitVector32, BitArray, or simply bitwise arithmetic to reduce this overhead. As variables I seem to recall they take 4 bytes (essentially handled as int = Int32).

例如，下面将 i 设置为 4:

For example, the following sets i to 4:

struct Foo
{
    public bool A, B, C, D;
}
static unsafe void Main()
{
    int i = sizeof(Foo);
}

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