bash 查找，仅删除文件 - 参数顺序 [英] bash find, only delete files - order of arguments

问题描述

假设今天是 4 月 8 日，我在 bash 中执行以下操作.

Say today is April 8th and I execute the following in bash.

cd /tmp
mkdir hello
touch -d 2015-04-01 hello

然后，假设我想删除/tmp 中所有超过一天的文件，但不是目录，我执行以下操作:

Then, say I want to delete all files in /tmp that are older than one day, but NOT directories and I execute this:

find /tmp -mtime +1 -delete -type f

如果不是文件，为什么目录hello"会被删除?

Why is directory "hello" deleted if it's not a file?

谢谢！

推荐答案

find命令按顺序执行表达式.由于 -delete 在 -type 之前，因此永远不会到达 -type.试试:

The find command executes the expression in order. Since -delete is before -type, -type is never reached. Try:

find /tmp -mtime +1 -type f -delete 

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