查找不在列表中的文件 [英] find files not in a list

问题描述

我在 file.lst 中有一个文件列表.现在我想查找目录 dir 中所有超过 7 天的文件，除了 file.lst 文件中的文件.如何修改 find 命令或从结果中删除 file.lst 中的所有条目?

I have a list of files in file.lst. Now I want to find all files in a directory dir which are older than 7 days, except those in the file.lst file. How can I either modify the find command or remove all entries in file.lst from the result?

例子:

file.lst:

a
b
c

执行:

find -mtime +7 -print > found.lst

found.lst:

a
d
e

所以我的期望是:

d
e

推荐答案

通过 grep -Fxvf 传递 find 命令:

Pipe your find command through grep -Fxvf:

find -mtime +7 -print | grep -Fxvf file.lst

标志的含义:

-F, --fixed-strings
              Interpret PATTERN as a list of fixed strings, separated by newlines, any of which is to be matched.    
-x, --line-regexp
              Select only those matches that exactly match the whole line.
-v, --invert-match
              Invert the sense of matching, to select non-matching lines.
-f FILE, --file=FILE
              Obtain patterns from FILE, one per line.  The empty file contains zero patterns, and therefore matches nothing.

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