gdb 无法访问内存地址错误 [英] gdb can't access memory address error
问题描述
这是我的 disas 代码:
here is my disas code:
0x0804844d <+0>: push %ebp
0x0804844e <+1>: mov %esp,%ebp
0x08048450 <+3>: and $0xfffffff0,%esp
0x08048453 <+6>: sub $0x20,%esp
0x08048456 <+9>: movl $0x8048540,(%esp)
0x0804845d <+16>: call 0x8048310 <puts@plt>
0x08048462 <+21>: lea 0x1c(%esp),%eax
0x08048466 <+25>: mov %eax,0x4(%esp)
0x0804846a <+29>: movl $0x8048555,(%esp)
0x08048471 <+36>: call 0x8048320 <scanf@plt>
0x08048476 <+41>: mov 0x1c(%esp),%eax
0x0804847a <+45>: cmp $0x208c,%eax
0x0804847f <+50>: jne 0x804848f <main+66>
0x08048481 <+52>: movl $0x8048558,(%esp)
0x08048488 <+59>: call 0x8048310 <puts@plt>
0x0804848d <+64>: jmp 0x804849b <main+78>
=> 0x0804848f <+66>: movl $0x8048569,(%esp)
0x08048496 <+73>: call 0x8048310 <puts@plt>
0x0804849b <+78>: mov $0x0,%eax
0x080484a0 <+83>: leave
0x080484a1 <+84>: ret
我要检查的是 $0x208c.当我输入 x/xw 0x208c 时,它返回错误,提示无法访问地址 0x208c 的内存.当我输入 Info registers 并查看 eax 时,它会显示我提供的值.所以基本上这个程序比较两个值,并根据它打印出一些东西.问题是这是大学的作业,我没有代码.希望你能帮忙.谢谢.
what i'm tring to examine is $0x208c. When I type x/xw 0x208c it gives me back error which says Cannot access memory at address 0x208c. When i type Info registers and look at eax it says the value which i provided. So basically this program compares two values and depending on that prints something out.The problem is that this is homework from university and I have not got code. Hope you can help. Thank you.
推荐答案
当我输入
x/xw 0x208c
时,它会返回错误提示Cannot access memory at address 0x208c
When I type
x/xw 0x208c
it gives me back error which saysCannot access memory at address 0x208c
你的程序的反汇编表明它做了这样的事情:
The disassembly for your program says that it does something like this:
puts("some string");
int i;
scanf("%d", &i); // I don't know what the actual format string is.
// You can find out with x/s 0x8048555
if (i == 0x208c) { ... } else { ... }
换句话说,0x208c
是您的程序硬编码在其中的值 (8332
),并且 不是指针.因此,GDB 完全正确地告诉您,如果您将 0x208c
解释为指针,则该指针不指向可读内存.
In other words, the 0x208c
is a value (8332
) that your program has hard-coded in it, and is not a pointer. Therefore, GDB is entirely correct in telling you that if you interpret 0x208c
as a pointer, that pointer does not point to readable memory.
我终于想出用 print 语句代替 x/xw
i finally figured out to use print statement instead of x/xw
您似乎不理解 print
和 examine
命令之间的区别.考虑这个例子:
You appear to not understand the difference between print
and examine
commands. Consider this example:
int foo = 42;
int *pfoo = &foo;
如上,print pfoo
会给你foo
的地址,x pfoo
会给你value 存储在该地址(即 foo
的值).
With above, print pfoo
will give you the address of foo
, and x pfoo
will give you the value stored at that address (i.e. the value of foo
).
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