有包含列表的 Pandas 列,如何将唯一列表元素旋转到列? [英] Have Pandas column containing lists, how to pivot unique list elements to columns?

查看:43
本文介绍了有包含列表的 Pandas 列,如何将唯一列表元素旋转到列?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我编写了一个网络爬虫来从产品表中提取信息并构建数据框.数据表有一个描述列,其中包含描述产品的属性的逗号分隔字符串.我想在数据框中为每个唯一属性创建一列,并用属性的子字符串填充该列中的行.下面的例子 df.

I wrote a web scraper to pull information from a table of products and build a dataframe. The data table has a Description column which contains a comma separated string of attributes describing the product. I want to create a column in the dataframe for every unique attribute and populate the row in that column with the attribute's substring. Example df below.

PRODUCTS     DATE        DESCRIPTION
Product A    2016-9-12   Steel, Red, High Hardness
Product B    2016-9-11   Blue, Lightweight, Steel
Product C    2016-9-12   Red

我认为第一步是将描述拆分成一个列表.

I figure the first step is to split the description into a list.

In: df2 = df['DESCRIPTION'].str.split(',')

Out:
DESCRIPTION
['Steel', 'Red', 'High Hardness']
['Blue', 'Lightweight', 'Steel']
['Red']

我想要的输出如下表所示.列名并不是特别重要.

My desired output looks like the table below. The column names are not particularly important.

PRODUCTS     DATE        STEEL_COL  RED_COL    HIGH HARDNESS_COL  BLUE COL   LIGHTWEIGHT_COL
Product A    2016-9-12   Steel      Red        High Hardness
Product B    2016-9-11   Steel                                    Blue       Lightweight
Product C    2016-9-12              Red

我相信可以使用 Pivot 设置列,但我不确定在建立列后填充列的最 Pythonic 方式.任何帮助表示赞赏.

I believe the columns can be set up using a Pivot but I'm not sure the most Pythonic way to populate the columns after establishing them. Any help is appreciated.

非常感谢您的回答.我选择@MaxU 的响应是正确的,因为它看起来稍微灵活一些,但@piRSquared 的结果非常相似,甚至可能被认为是更Pythonic 的方法.我测试了两个版本,都做了我需要的.谢谢!

Thank you very much for the answers. I selected @MaxU's response as correct since it seems slightly more flexible, but @piRSquared's gets a very similar result and may even be considered the more Pythonic approach. I tested both version and both do what I needed. Thanks!

推荐答案

你可以建立一个稀疏矩阵:

you can build up a sparse matrix:

In [27]: df
Out[27]:
    PRODUCTS       DATE                DESCRIPTION
0  Product A  2016-9-12  Steel, Red, High Hardness
1  Product B  2016-9-11   Blue, Lightweight, Steel
2  Product C  2016-9-12                        Red

In [28]: (df.set_index(['PRODUCTS','DATE'])
   ....:    .DESCRIPTION.str.split(',s*', expand=True)
   ....:    .stack()
   ....:    .reset_index()
   ....:    .pivot_table(index=['PRODUCTS','DATE'], columns=0, fill_value=0, aggfunc='size')
   ....: )
Out[28]:
0                    Blue  High Hardness  Lightweight  Red  Steel
PRODUCTS  DATE
Product A 2016-9-12     0              1            0    1      1
Product B 2016-9-11     1              0            1    0      1
Product C 2016-9-12     0              0            0    1      0

In [29]: (df.set_index(['PRODUCTS','DATE'])
   ....:    .DESCRIPTION.str.split(',s*', expand=True)
   ....:    .stack()
   ....:    .reset_index()
   ....:    .pivot_table(index=['PRODUCTS','DATE'], columns=0, fill_value='', aggfunc='size')
   ....: )
Out[29]:
0                   Blue High Hardness Lightweight Red Steel
PRODUCTS  DATE
Product A 2016-9-12                  1               1     1
Product B 2016-9-11    1                         1         1
Product C 2016-9-12                                  1

这篇关于有包含列表的 Pandas 列,如何将唯一列表元素旋转到列?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆