RestSharp JSON参数发布 [英] RestSharp JSON Parameter Posting
本文介绍了RestSharp JSON参数发布的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想提出一个非常基本的REST调用到我的MVC 3 API和我通过在这些参数不会绑定到操作方法。
I am trying to make a very basic REST call to my MVC 3 API and the parameters I pass in are not binding to the action method.
客户端
var request = new RestRequest(Method.POST);
request.Resource = "Api/Score";
request.RequestFormat = DataFormat.Json;
request.AddBody(request.JsonSerializer.Serialize(new { A = "foo", B = "bar" }));
RestResponse response = client.Execute(request);
Console.WriteLine(response.Content);
服务器
public class ScoreInputModel
{
public string A { get; set; }
public string B { get; set; }
}
// Api/Score
public JsonResult Score(ScoreInputModel input)
{
// input.A and input.B are empty when called with RestSharp
}
我失去了一些东西在这里?
Am I missing something here?
推荐答案
您不必自己序列化的身体。只要做到
You don't have to serialize the body yourself. Just do
request.RequestFormat = DataFormat.Json;
request.AddBody(new { A = "foo", B = "bar" }); // uses JsonSerializer
如果你只是想POST PARAMS,而不是(这将仍然映射到你的模型和很多更有效,因为没有序列化到JSON)做到这一点:
If you just want POST params instead (which would still map to your model and is a lot more efficient since there's no serialization to JSON) do this:
request.AddParameter("A", "foo");
request.AddParameter("B", "bar");
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