如何将浮点值四舍五入到小数点后 2 位? [英] How can I round a float value to 2 post decimal positions?

问题描述

我从加速度计得到一个浮点值，如下所示:

I've got a float value from an accelerometer which looks like this:

-3.04299553323

-3.04299553323

例如，我想得到 -3.04.有没有一种简单的方法来舍入该浮点值?

I'd like to get -3.04 for example. Is there an easy way for rounding that float value?

Objective-C 中的四舍五入

推荐答案

我知道这是旧帖子，但以防万一其他人正在寻找快速的两步选项.

I know this is old post but just in case someone else is looking for a quick Two step option.

float old = -3.04299553323;  
float new = [[NSString stringWithFormat:@"%.2f",old]floatValue];

结果 = -3.04

@"%.2f" 将四舍五入到小数点后两位.如果您想要三位小数，请输入 @"%.3f" 等等.

The @"%.2f" will round to two decimal places. If you want three decimal places put @"%.3f" and so on.

希望这会有所帮助！

这篇关于如何将浮点值四舍五入到小数点后 2 位?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！