在 VB.NET 中声明一个十六进制常量 [英] Declaring a hex constant in VB.NET

问题描述

如何将以下 C# 十六进制转换为 VB.NET 十六进制?

How can I convert the following C# hexadecimal into a VB.NET hexadecimal?

private const UInt32 temp = 0xE6359A60;

我尝试了以下方法，但它不起作用.

I tried the following, but it doesn't work.

Public Const temp As System.UInt32 = 0xE6359A60

推荐答案

C# 使用 0x 和 VB.NET 使用 &H 作为前缀来指定十六进制数.试试这个.

C# uses 0x and VB.NET uses &H as the prefix to specify hexadecimal numbers. try this.

Public Const temp As Integer = &HE6359A60

Sub Main

End Sub

它也可以是 Uint:

And it could be as Uint also:

Public Const temp As UInt32 = &HE6359A60UI

Sub Main

End Sub

查看 MSDN 的 Type Characters (Visual Basic) 文档以定义十六进制和八进制文字:

Check MSDN's Type Characters (Visual Basic) documentation for defining hexadecimal and octal literals:

编译器通常将整数文字解释为十进制(以 10 为底)数字系统.您可以强制整数文字十六进制(以 16 为基数) 加上 &H 前缀，你可以强制它八进制(以 8 为基数)，带有 &O 前缀.后面的数字前缀必须适合数字系统.

The compiler normally construes an integer literal to be in the decimal (base 10) number system. You can force an integer literal to be hexadecimal (base 16) with the &H prefix, and you can force it to be octal (base 8) with the &O prefix. The digits that follow the prefix must be appropriate for the number system.

参考资料:

• 十六进制数(不是 ASCII 十六进制值)到 VB.NET 中的字符串(堆栈溢出)
• &H57 代表什么以及如何将其翻译为 C#?(堆栈溢出)

• Hex number (not ASCII hex value) to string in VB.NET (Stack Overflow)
• What does &H57 represent and how can I translate it for C#? (Stack Overflow)

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