如何在布局上膨胀 ImageView 对象的新副本? [英] How to inflate new copies of an ImageView object on a layout?

问题描述

我要做的是创建 ImageView 对象 R.id.tile 的 N(在本例中为 9 个)副本，将它们中的每一个放在不同的坐标在布局上，并为每个布局赋予其唯一标识符.

What I am trying to do is create N (in this case 9) copies of the ImageView object R.id.tile, place each of them at different coordinates on the layout, and give each its own unique identifier.

board_layout.xml:

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:background="@drawable/backgroundcolor"
    android:orientation="vertical" >

    <LinearLayout
        android:id="@+id/topbar"
        ... >

        <ImageButton
            android:id="@+id/imagebutton"
            ... />

    </LinearLayout>

    <RelativeLayout
        android:id="@+id/board"
        android:layout_width="match_parent"
        android:layout_height="345dp"
        android:layout_centerVertical="true"
        android:background="@drawable/wwfboard" >

        <view class="languid.legend.xsolver.DrawView"
            android:id="@+id/myView"
            android:layout_width="fill_parent"
            android:layout_height="fill_parent" />

        <ImageView
            android:id="@+id/tile"
            android:layout_width="21dp"
            android:layout_height="21dp"
            android:src="@drawable/tile" />
    </RelativeLayout>

</RelativeLayout>

BoardLayout.class:

@Override
protected void onCreate(Bundle savedInstance)
{   super.onCreate(savedInstance);
    setContentView(R.layout.board_layout);
    LayoutInflater inflater = (LayoutInflater)this.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
    View[] tiles = new ImageView[9];
    entire_layout = (RelativeLayout)findViewById(R.layout.board_layout);


    for(int i = 0; i<tiles.length; i++){
        tiles[i] = (ImageView) inflater.inflate(R.layout.board_layout, null);
        tiles[i].setId(1000+i);
        params = new RelativeLayout.LayoutParams(-1, 345);
        params.leftMargin = 32*2*i;
        params.topMargin = 34*2*i;
        entire_layout.addView(tiles[i]);
    }
    ...

但是，我在最后一行不断收到 Source not found" 错误:layout.addView(tiles[i]);..

任何想法为什么?

(附带问题:如果您使用坐标，RelativeLayout 是否比 AbsoluteLayout 更好?)

However, I keep getting "Source not found" errors on the last line: layout.addView(tiles[i]);..

Any ideas why?

(Side question: is RelativeLayout better than AbsoluteLayout if you're working with coordinates?)

推荐答案

首先创建一个带有你喜欢的属性的 ImageView 的布局

First create a layout with one ImageView with the properties you like

例子:

在 res/layout/singleimage.xml 中创建文件

<?xml version="1.0" encoding="utf-8"?>
<ImageView xmlns:android="http://schemas.android.com/apk/res/android"
           android:id="@+id/image2"
           android:layout_width="match_parent"
           android:layout_height="match_parent"
           android:src="@drawable/ic_launcher"
           android:contentDescription="Sample"/>

然后对 ImageView 进行膨胀以获取它的副本，像这样

And then inflate the ImageView to get the copies of it like this

View[] tiles = new ImageView[9];
// get reference to LayoutInflater
LayoutInflater inflater = (LayoutInflater) this.getSystemService(Context.LAYOUT_INFLATER_SERVICE);

for(int i = 0; i<tiles.length; i++) {
    //Creating copy of imageview by inflating it
    ImageView image = (ImageView) inflater.inflate(R.layout.singleimage, null);
    tiles[i] = image;
    tiles[i].setId(i);
    RelativeLayout.LayoutParams params = new RelativeLayout.LayoutParams(-1, 345);
    params.leftMargin = 32*2*3;
    params.topMargin = 34*2*3;
    layout.addView(tiles[i]);
}

<小时>

您已在此处将 id 设置为 i 值

tiles[i].setId(i);  

但是您(错误地)试图从您的其他资源(您想要克隆"的资源)中获取它:

But you are (incorrectly) trying to get it from your other resource (the one you wanted to 'clone'):

layout.addView(tiles[i] = (ImageView) findViewById(R.id.tile)); // INCORRECT

相反，像上面一样手动设置id，然后:

Instead, set the id manually as above, and then:

layout.addView(tiles[i]);

而且不需要调用findViewById()

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