如何制作一个按钮，单击时会打开 %appdata% 目录? [英] How to make a button that, when clicked, opens the %appdata% directory?

问题描述

我已经制作了一个按钮，但我现在不知道如何在单击按钮时打开一个特定的目录，例如 %appdata%.

I have made a button, but I don't now how to make it open a specific directory like %appdata% when the button is clicked on.

这里是代码->

//---- button4 ----
        button4.setText("Texture Packs");
        button4.addActionListener(new ActionListener() {
            public void actionPerformed(ActionEvent e)
            {
                JFileChooser fileChooser=new JFileChooser("%appdata%");
                int status = fileChooser.showOpenDialog(this);
                fileChooser.setMultiSelectionEnabled(false);

                if(status == JFileChooser.APPROVE_OPTION) {
                    File file = fileChooser.getSelectedFile();
                    // do something on the selected file.
                }


            }

我想做这样的东西->

private void button4MouseClicked(MouseEvent e) throws IOException {

           open folder %appdata% 
           // Open the folder in the file explorer not in Java.
           // When I click on the button, the folder is viewed with the file explorer on the screen
        }

推荐答案

import java.awt.Desktop;
import java.io.File;

public class OpenAppData {

    public static void main(String[] args) throws Exception {
        // Horribly platform specific.
        String appData = System.getenv("APPDATA");
        File appDataDir = new File(appData);
        // Get a sub-directory named 'texture'
        File textureDir = new File(appDataDir, "texture");
        Desktop.getDesktop().open(textureDir);
    }
}

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