一种区分日志文件的简单方法，忽略时间戳? [英] An easy way to diff log files, ignoring the time stamps?

问题描述

我需要区分两个日志文件，但忽略每行的时间戳部分(准确地说是前 12 个字符).有什么好的工具，或者聪明的 awk 命令可以帮助我吗?

I need to diff two log files but ignore the time stamp part of each line (the first 12 characters to be exact). Is there a good tool, or a clever awk command, that could help me out?

推荐答案

根据你使用的shell，可以转方法@Blair 建议使用 1-liner

Depending on the shell you are using, you can turn the approach @Blair suggested into a 1-liner

diff <(cut -b13- file1) <(cut -b13- file2)

(+1 到 @Blair 对于最初的建议 :-)

(+1 to @Blair for the original suggestion :-)

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