Django Admin，显示来自相关模型的聚合值 [英] Django Admin, Show Aggregate Values From Related Model

问题描述

是否可以在单个 Django 管理模型中聚合相关对象的字段.

Is it possible, within a single Django admin model, to aggregate fields from related objects.

例如，我有一个学生对象，它对测试对象有一个 FK.测试对象有一个分数"字段.

For example, I have a Student Object that has a FK to a Test Object. The test object has a "score" field.

我可以汇总所有学生考试的分数并将其放在管理 display_list 属性中吗?

Can I aggregate the scores across all Student's Tests and place it in the admin display_list attribute?

推荐答案

你可以，例如:

class FixtureAdmin(admin.ModelAdmin): 
    list_display = ["id", "title", "date", "num_fixture_metas_count"]

    def get_queryset(self, request):
        qs = super(FixtureAdmin, self).get_queryset(request)
        return qs.annotate(num_fixture_metas=Count('fixturemeta'))

    def num_fixture_metas_count(self, obj):
      return obj.num_fixture_metas
    num_fixture_metas_count.short_description = 'Fixture Count'
    num_fixture_metas_count.admin_order_field = 'num_fixture_metas'

但是，AFAIK，您不能通过此方法在这些字段的管理员中单击排序，因为将 .annotate() 中的 num_fixture_metas 添加到 >list_display 导致缺少字段错误.

However, AFAIK, you cannot click sort within the admin on these fields via this method, as adding num_fixture_metas from .annotate() to the list_display results in a missing field error.

https://docs.djangoproject.com/en/dev/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_displayhttps://docs.djangoproject.com/en/dev/topics/db/聚合/

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