传递到字典的模型项的类型是“System.Data.Entity.DynamicProxies.Object [英] The model item passed into the dictionary is of type 'System.Data.Entity.DynamicProxies.Object
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问题描述
有谁知道为什么我收到此错误:
模型项目传递到字典类型
system.Data.Entity.DynamicProxies.Object_3E186F803589BF82895B10E08C
2A9AB68EFA619599418D6EB96585D14874CDC0',
但本词典需要类型的模型项目
System.Collections.Generic.IEnumerable`1 [MyApplication.Domain.Entities.Object]。
下面是我的code:
控制器:
公开的ViewResult指数()
{
如果(User.Identity.IsAuthenticated)
{
的MembershipUser的currentUser = Membership.GetUser();
GUID currentUserId =(GUID)currentUser.ProviderUserKey;
如果(的currentUser = NULL&放大器;!&安培; currentUser.ProviderUserKey = NULL&放大器;!&安培; currentUser.IsApproved)
{
此举的结果=(从db.Moves招
其中,move.UserId == currentUserId
选择移动).FirstOrDefault();
返回视图(结果);
}
}
返回查看(db.Moves.ToList());
}
查看:
@model IEnumerable的< MovinMyStuff.Domain.Entities.Move>
@ {
ViewBag.Title =指数;
}@foreach(以型号VAR项)
{
< DIV ID =移动列表项>
< UL>
<立GT;
<跨度类=动名>
@ Html.DisplayFor(modelItem => item.StartCity)
@ Html.DisplayFor(modelItem => item.StartState)
@ Html.DisplayFor(modelItem => item.StartZip) -
@ Html.DisplayFor(modelItem => item.EndCity)
@ Html.DisplayFor(modelItem => item.EndState)
@ Html.DisplayFor(modelItem => item.EndZip)
< / SPAN>
< /李>
<立GT; @ Html.ActionLink(详细信息,详细信息,新{ID = item.MoveId},{新@class =按钮})LT; /李>
< / UL>
< / DIV>
}
解决方案
这code:
移动结果=(从db.Moves招
其中,move.UserId == currentUserId
选择移动).FirstOrDefault();
返回视图(结果);
试图返回的单的结果。它的抱怨就是了序的结果。所以,你可以只使用:
VAR的结果=(从db.Moves招
其中,move.UserId == currentUserId
选择移动)。取(1).ToList();
返回查看(结果);
或者
移动结果=(从db.Moves招
其中,move.UserId == currentUserId
选择移动).FirstOrDefault();
返回查看(新[] {结果});
我个人摆脱查询前pression这里,顺便说一句 - 这是使code比它需要的更加复杂。例如,您可以重写我的第一个选项为:
VAR的结果= db.Moves.Where(移动=> move.UserId == currentUserId)
。取(1)
.ToList();
返回查看(结果);
甚至
返回查看(db.Moves.Where(移动=> move.UserId == currentUserId)
。取(1).ToList());
Does anyone know why I am getting this error:
The model item passed into the dictionary is of type
system.Data.Entity.DynamicProxies.Object_3E186F803589BF82895B10E08C
2A9AB68EFA619599418D6EB96585D14874CDC0',
but this dictionary requires a model item of type
'System.Collections.Generic.IEnumerable`1[MyApplication.Domain.Entities.Object]'.
Here is my code:
Controller:
public ViewResult Index()
{
if (User.Identity.IsAuthenticated)
{
MembershipUser currentUser = Membership.GetUser();
Guid currentUserId = (Guid)currentUser.ProviderUserKey;
if (currentUser != null && currentUser.ProviderUserKey != null && currentUser.IsApproved)
{
Move result = (from move in db.Moves
where move.UserId == currentUserId
select move).FirstOrDefault();
return View(result);
}
}
return View(db.Moves.ToList());
}
View:
@model IEnumerable<MovinMyStuff.Domain.Entities.Move>
@{
ViewBag.Title = "Index";
}
@foreach (var item in Model)
{
<div id="move-list-item">
<ul>
<li>
<span class="move-name">
@Html.DisplayFor(modelItem => item.StartCity)
@Html.DisplayFor(modelItem => item.StartState)
@Html.DisplayFor(modelItem => item.StartZip) -
@Html.DisplayFor(modelItem => item.EndCity)
@Html.DisplayFor(modelItem => item.EndState)
@Html.DisplayFor(modelItem => item.EndZip)
</span>
</li>
<li>@Html.ActionLink("Details", "Details", new { id = item.MoveId }, new { @class = "button" })</li>
</ul>
</div>
}
解决方案
This code:
Move result = (from move in db.Moves
where move.UserId == currentUserId
select move).FirstOrDefault();
return View(result);
tries to return a single result. It's complaining that it wants a sequence of results. So you could just use:
var results = (from move in db.Moves
where move.UserId == currentUserId
select move).Take(1).ToList();
return View(results);
Or:
Move result = (from move in db.Moves
where move.UserId == currentUserId
select move).FirstOrDefault();
return View(new[] { result });
I would personally get rid of the query expression here, by the way - it's make the code more complicated than it needs to be. For example, you could rewrite my first option as:
var results = db.Moves.Where(move => move.UserId == currentUserId)
.Take(1)
.ToList();
return View(results);
Or even:
return View(db.Moves.Where(move => move.UserId == currentUserId)
.Take(1).ToList());
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