按顺序创建重复值序列? [英] Create sequence of repeated values, in sequence?

问题描述

我需要一个重复数字的序列，即 1 1 ... 1 2 2 ... 2 3 3 ... 3 等. 我的实现方式是:

I need a sequence of repeated numbers, i.e. 1 1 ... 1 2 2 ... 2 3 3 ... 3 etc. The way I implemented this was:

  nyear <- 20
  names <- c(rep(1,nyear),rep(2,nyear),rep(3,nyear),rep(4,nyear),
             rep(5,nyear),rep(6,nyear),rep(7,nyear),rep(8,nyear))

这可行，但很笨拙，而且显然不能很好地扩展.

which works, but is clumsy, and obviously doesn't scale well.

如何将N个整数依次重复M次?

• 我尝试嵌套 seq() 和 rep() 但这并没有达到我想要的效果.
• 我显然可以编写一个 for 循环来做到这一点，但应该有一种内在的方式来做到这一点！

• I tried nesting seq() and rep() but that didn't quite do what I wanted.
• I can obviously write a for-loop to do this, but there should be an intrinsic way to do this!

推荐答案

你错过了 rep() 的 each= 参数:

You missed the each= argument to rep():

R> n <- 3
R> rep(1:5, each=n)
 [1] 1 1 1 2 2 2 3 3 3 4 4 4 5 5 5
R> 

所以你的例子可以用一个简单的来完成

so your example can be done with a simple

R> rep(1:8, each=20)

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