PHP数组按值删除(不是键) [英] PHP array delete by value (not key)

问题描述

我有一个PHP数组如下:

I have a PHP array as follows:

$messages = [312, 401, 1599, 3, ...];

我想删除包含值 $del_val 的元素(例如，$del_val=401)，但我不知道它的键.这可能会有所帮助:每个值只能出现一次.

I want to delete the element containing the value $del_val (for example, $del_val=401), but I don't know its key. This might help: each value can only be there once.

我正在寻找执行此任务的最简单函数.

I'm looking for the simplest function to perform this task, please.

推荐答案

使用 <代码>array_search() 和 unset，尝试以下方法:

Using array_search() and unset, try the following:

if (($key = array_search($del_val, $messages)) !== false) {
    unset($messages[$key]);
}

array_search() 返回它找到的元素的键，可用于使用 unset() 从原始数组中删除该元素.它会在失败时返回 FALSE，但是它可以在成功时返回 false-y 值(例如，您的键可能是 0)，这就是为什么严格比较 !== 运算符.

array_search() returns the key of the element it finds, which can be used to remove that element from the original array using unset(). It will return FALSE on failure, however it can return a false-y value on success (your key may be 0 for example), which is why the strict comparison !== operator is used.

if() 语句将检查 array_search() 是否返回了值，如果返回则只执行操作.

The if() statement will check whether array_search() returned a value, and will only perform an action if it did.

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