VHDL多个常量驱动器 [英] VHDL multiple constant drivers
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问题描述
我正在尝试使用开关和祸不单行显示修改做和(例如)和其他数学函数的源代码。
这是主代码:
library ieee;
use ieee.std_logic_1164.all;
use ieee.numeric_std.all;
use work.seven_segment_pkg.all;
entity Switch7Segment is
port (
SW : in std_logic_vector(9 downto 0);
HEX0 : out std_logic_vector(6 downto 0);
HEX1 : out std_logic_vector(6 downto 0);
HEX2 : out std_logic_vector(6 downto 0);
HEX3 : out std_logic_vector(6 downto 0);
KEY : in std_logic_vector(3 downto 0);
CLOCK_50 : in std_logic
);
end entity Switch7Segment;
architecture behavior of Switch7Segment is
signal segments1 : std_logic_vector(13 downto 0);
signal segments2 : std_logic_vector(13 downto 0);
signal segmentsR : std_logic_vector(13 downto 0); -- Range changed from 27 downto 0 to allow compile
signal input1 : integer;
signal input2 : integer;
signal result : unsigned(31 downto 0); -- Range added to allow compile
signal temp : integer;
begin
input1 <= to_integer(unsigned(SW(4 downto 0)));
input2 <= to_integer(unsigned(SW(9 downto 5)));
segments1 <= unsigned_to_seven_segment(value => unsigned(SW(4 downto 0)), number_of_digits => 2, value_is_bcd => false);
segments2 <= unsigned_to_seven_segment(value => unsigned(SW(9 downto 5)), number_of_digits => 2, value_is_bcd => false);
HEX1 <= segments1(13 downto 7);
HEX0 <= segments1(6 downto 0);
HEX3 <= segments2(13 downto 7);
HEX2 <= segments2(6 downto 0);
process(CLOCK_50)
begin
if (CLOCK_50' EVENT and CLOCK_50 = '1' AND KEY(0) = '1') then
temp <= input1+input2;
result <= to_unsigned(integer(temp), result'length);
segmentsR <= unsigned_to_seven_segment(value => unsigned(result), number_of_digits => 2, value_is_bcd => false);
HEX1 <= segmentsR(13 downto 7);
HEX0 <= segmentsR(6 downto 0);
end if;
end process;
end architecture;
然后是包:
library ieee;
use ieee.std_logic_1164.all;
use ieee.numeric_std.all;
package seven_segment_pkg is
-- Return a std_logic_vector ready for driving a number of 7-segment displays.
function unsigned_to_seven_segment(value : unsigned; number_of_digits : integer; value_is_bcd : boolean)
return std_logic_vector;
end;
package body seven_segment_pkg is
function seven_seg_from_bcd_digit(bcd_digit : std_logic_vector(3 downto 0)) return std_logic_vector is
begin
case bcd_digit is
-- abcdefg
when x"0" => return "1000000";
when x"1" => return "1111001";
when x"2" => return "0100100";
when x"3" => return "0110000";
when x"4" => return "0011001";
when x"5" => return "0010010";
when x"6" => return "0000010";
when x"7" => return "1111000";
when x"8" => return "0000000";
when x"9" => return "0010000";
when x"a" => return "0001000";
when x"b" => return "0000011";
when x"c" => return "1000110";
when x"d" => return "0100001";
when x"e" => return "0000110";
when x"f" => return "1110001";
when others => return "0000000";
end case;
end function;
-- Return a vector ready for driving a series of 7-segment displays.
function unsigned_to_seven_segment(
value : unsigned;
-- Number of 7-segment displays (determines output vector width: W = 7*N)
number_of_digits : integer;
-- When true, treat the input value as a BCD number where every 4 bits hold one
-- digit from 0 to A. When false, treat the input number as an unsigned integer.
value_is_bcd : boolean
) return std_logic_vector is
variable segments : std_logic_vector(number_of_digits*7-1 downto 0);
variable bcd_quotient : unsigned(value'range);
variable bcd_remainder : unsigned(3 downto 0);
begin
if value_is_bcd then
for i in 0 to number_of_digits-1 loop
segments(i*7+6 downto i*7) := seven_seg_from_bcd_digit(
std_logic_vector(value(i*4+3 downto i*4))
);
end loop;
else
bcd_quotient := value;
for i in 0 to number_of_digits-1 loop
bcd_remainder := resize(bcd_quotient mod 10, 4);
bcd_quotient := bcd_quotient / 10;
segments(i*7+6 downto i*7) := seven_seg_from_bcd_digit(
std_logic_vector(bcd_remainder)
);
end loop;
end if;
return segments;
end function;
end package body;
我认为有一个错误,目前我没有在这里签名,这就是结果的长度。如果我们编译这段VHDL代码,Quartus会告诉我们该函数是针对13个元素的,而不是针对27个元素的。但是我看不到解决它的障碍.我的问题是关于输出(HEX0.HEX3)
如果我修改代码并插入
signal segmentsR: std_logic_vector(13 downto 0);
我解决了长度问题,但会看到错误10028(多个常量驱动程序)。
如果我理解正确,我不能在同一向量上赋值两次,两个不同的值或类似的东西是正确的吗?也许我总是像一个C++/C程序员一样思考。我想如果我用时钟,问题会解决,但不是真的…
推荐答案
问题是HEX0
和HEX1
在进程之前和进程中都有驱动程序,但任何信号/端口都应该仅从典型合成代码中的一个位置驱动。
如果HEX0
和HEX1
从进程中驱动,则在进程之前删除驱动程序。
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