如果JSON数据包含换行符(&Q;),则SWIFT 4无法正确解码 (&Q;) [英] Swift 4 can't decode properly if json data contain new line (" ")

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本文介绍了如果JSON数据包含换行符(&Q;),则SWIFT 4无法正确解码 (&Q;)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

如果json数据包含新行(""),则SWIFT 4无法正确解码 ")。我能为这个案例做些什么。请查看我的样例代码:

var userData = """
[
 {
  "userId": 1,
 "id": 1,
 "title": "Title 
 with newline",
 "completed": false
 }
]
""".data(using: .utf8)

struct User: Codable{
var userId: Int
var id: Int
var title: String
var completed: Bool
 }

do {
//here dataResponse received from a network request
let decoder = JSONDecoder()
let model = try decoder.decode([User].self, from:userData!) //Decode JSON Response Data
    print(model)
} catch let parsingError {
    print("Error", parsingError)
}

如果我按如下所示更改用户数据值,则它可以正确解码。

var userData = """
[
     {
      "userId": 1,
     "id": 1,
     "title": "Title \n with newline",
     "completed": false
     }
]
""".data(using: .utf8)

推荐答案

这是无效的json。 "" [ { "userid":1, "id":1, "title":"标题 带换行符", "Complete":False } ] "

请使用以下代码

var userData : [[String:Any]] =
[
 [
   "userId": 1,
   "id": 1,
   "title": "Title 
 with newline",
   "completed": false
 ]
]

struct User: Codable{
    var userId: Int
    var id: Int
    var title: String
    var completed: Bool
 }

do {
   //here dataResponse received from a network request
    let data = try? JSONSerialization.data(withJSONObject: userData, options: 
[])

    let decoder = JSONDecoder()
    let model = try decoder.decode([User].self, from:data!) //Decode JSON 
    Response Data
    print(model)
} catch let parsingError {
   print("Error", parsingError)
}

这篇关于如果JSON数据包含换行符(&Q;),则SWIFT 4无法正确解码 (&Q;)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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