从R中的netcdf创建栅格最准确的方法是什么? [英] What is the most accurate way of creating a raster from netcdf in R?

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问题描述

我处理netCDF数据已多年。NetCDF用于空气污染物数据,纬度和经度作为单独的变量提供,而不是原始网格的一部分。

链接到日期:Sample Netcdf

这些netCDF文件提供2级二氧化氮数据,可从NASA EarthData门户网站下载。卫星是Sentinel-5P,仪器是Tropomi。

因此,在处理这些数据时,您必须为NO2、纬度和经度创建变量。我正在尝试创建栅格图层,然后将它们另存为GeoTIFF文件以供我的研究。

这里的问题与我不知道如何最好地创建这些栅格有关。纬度和经度在整个数据集中的间距不相等,我还没有想出一种方法来准确地创建这些图像。我使用netCDF文件提供的行数和列数创建了一个模型网格。在变量列表中,这称为扫描线和GROUND_Pixel,但当我绘制它时,最终图像中的单元格看起来不正确。

我是这样上传数据的:

## Open the netcdf
  ncname <- no2files$filename[m]
  ncfname <- paste(ncname, sep = "")
  nc <- nc_open(ncfname)
  
  ## Get the necessary variables. 
  no2tc <-ncvar_get(nc, "PRODUCT/nitrogendioxide_tropospheric_column")
  lat <- ncvar_get(nc, "PRODUCT/latitude")
  lon <- ncvar_get(nc, "PRODUCT/longitude")
  qa <- ncvar_get(nc, "PRODUCT/qa_value")
  
  fillvalue = ncatt_get(nc, "DETAILED_RESULTS/nitrogendioxide_total_column",
                  "_FillValue")
  mfactor <- ncatt_get(nc, "DETAILED_RESULTS/nitrogendioxide_total_column",
                  "multiplication_factor_to_convert_to_molecules_percm2")
  
  fillvalue_qa = ncatt_get(nc,"PRODUCT/qa_value",
                  "_FillValue")
  
  
  
  no2tc[no2tc == fillvalue$value] <- NA
  no2tc <- no2tc * mfactor$value
  
  qa[qa == fillvalue_qa$value] <- NA
  
  nc_close(nc)
  # rm(ncfname)
  
  no2vec <- as.vector(no2tc)
  latvec <- as.vector(lat)
  lonvec <- as.vector(lon)
  qavec <- as.vector(qa)
  
  dfsat <- data.frame(no2vec, lonvec, latvec)
  dfqa <- data.frame(qavec,lonvec,latvec)
  
  colnames(dfsat) <- c('z', 'x', 'y')
  colnames(dfqa) <- c('z', 'x', 'y')
  
  df <- rbind(df, dfsat)
  dfqa <- rbind(df,dfqa)
  rm(lat,lon,no2tc,qa,latvec,lonvec,no2vec,qavec)

这是我当前创建栅格的方式:

  ## Create the raster. The ncol = 3245 and now = 450 are from the scanline and ground_pixel variables. 
  e <- extent(-180,180,-90,90)
  r <- raster(e, ncol = 3245, nrow = 450)
  
  xx <- rasterize(df[, 2:3], r, df[, 1], fun = mean)
  qa_raster <- rasterize(dfqa[, 2:3], r, df[, 1], fun = mean)
  
  crs(xx) <- "+proj=longlat +datum=WGS84 +no_defs +ellps=WGS84 +towgs84=0,0,0"
  crs(qa_raster) <- "+proj=longlat +datum=WGS84 +no_defs +ellps=WGS84 +towgs84=0,0,0"
  
  ## Crop and plot the raster
  ## change shapefile coordinate system 
  # border <- spTransform(ontario, crs(xx))
  aoi <- spTransform(ontario_buffer, crs(xx))
  
  ## Mask values with qa < 0.5 (this is the recommended value)
  
  xx[qa_raster < 0.5 & xx < 0] <- NA

  
  ## This is the final plot
  plot_tif <- crop(xx, extent(aoi))

  ### Use this if you want to view the plot. 
  mask_tif <- mask(plot_tif,aoi)
  # plot(mask_tif)
  # final <- plot(border,add=TRUE)
  
  ## Plot the raster 
  filename <- paste(i,".tif",sep="")
  writeRaster(mask_tif,filename = filename,"GTiff", overwrite=TRUE)

最终结果如下:

然后我尝试了我在网上找到的另一种方法,但您必须设置分辨率。我可以这样做,但我只想按原样绘制单元格,不做任何修改。

ncfname <- "S5P_OFFL_L2__NO2____20200107T173517_20200107T191647_11582_01_010302_20200109T103930.nc"

nc <- ncdf4::nc_open(ncfname)

mfactor = ncdf4::ncatt_get(nc, "PRODUCT/nitrogendioxide_tropospheric_column","multiplication_factor_to_convert_to_molecules_percm2")
fillvalue = ncdf4::ncatt_get(nc, "PRODUCT/nitrogendioxide_tropospheric_column","_FillValue")
my_unit = ncdf4::ncatt_get(nc, "PRODUCT/nitrogendioxide_tropospheric_column","units")
my_product_name = ncdf4::ncatt_get(nc, "PRODUCT/nitrogendioxide_tropospheric_column", "long_name")

mfactor <- mfactor$value

fillvalue <- fillvalue$value

vals <- ncdf4::ncvar_get(nc, "PRODUCT/nitrogendioxide_tropospheric_column")
lat <- ncdf4::ncvar_get(nc, "PRODUCT/latitude")
lon <- ncdf4::ncvar_get(nc, "PRODUCT/longitude")
vals[vals == fillvalue] <- NA

vals_df = NULL

vals_df <- rbind(vals_df, data.frame(lat = as.vector(lat), lon = as.vector(lon), vals = as.vector(vals)))

pts <- vals_df

sp::coordinates(pts) <- ~lon + lat

my_projection <- "+proj=longlat +datum=WGS84 +no_defs +ellps=WGS84 +towgs84=0,0,0"

sp::proj4string(pts) <- sp::CRS(my_projection)

my_aoi <- ontario

crs_test <- raster::compareCRS(pts, my_aoi)

my_aoi <- sp::spTransform(my_aoi, CRS = as.character(raster::crs(pts)))


p <- methods::as(raster::extent(my_aoi), "SpatialPolygons")

sp::proj4string(p) <- sp::CRS(my_projection)

pts <- raster::crop(pts, p)

extent_distance_vertical <- geosphere::distm(c(raster::extent(pts)[1],                  raster::extent(pts)[3]), c(raster::extent(pts)[1], raster::extent(pts)[4]), 
                                               fun = geosphere::distHaversine)
  
vertical_mid_distance <- (raster::extent(pts)[4] - raster::extent(pts)[3])/2

lat_mid <- raster::extent(pts)[3] + vertical_mid_distance

horizontal_distance <- raster::extent(pts)[2] - raster::extent(pts)[1]
  

if (horizontal_distance > 180) {
  one_degree_horizontal_distance <- geosphere::distm(c(1,
                                                       lat_mid), c(2, lat_mid), fun = geosphere::distHaversine)
  extent_distance_horizontal <- one_degree_horizontal_distance *
    horizontal_distance
} else {
  extent_distance_horizontal <-
    geosphere::distm(c(raster::extent(pts)[1],
                       lat_mid),
                     c(raster::extent(pts)[2], lat_mid),
                     fun = geosphere::distHaversine)
}


my_res <- 20000
ncol_rast <- as.integer(extent_distance_horizontal/my_res)
nrow_rast <- as.integer(extent_distance_vertical/my_res)
print(paste0("Create raster file from points"))
rast <- raster::raster(nrows = nrow_rast, ncols = ncol_rast, 
                         crs = as.character(raster::crs(pts)), ext = raster::extent(pts), 
                         vals = NULL)
final <- raster::rasterize(pts, rast, pts$vals, fun = mean)

final <- raster::mask(final, my_aoi)

sp::plot(final)

如何准确创建这些栅格层?谢谢!

推荐答案

使用示例文件

f <- "S5P_OFFL_L2__NO2____20200107T173517_20200107T191647_11582_01_010302_20200109T103930.nc"

您可以

library(terra)
r <- rast(f, paste0("/PRODUCT/", c("longitude", "latitude", "nitrogendioxide_tropospheric_column")))
r
#class       : SpatRaster 
#dimensions  : 4172, 450, 3  (nrow, ncol, nlyr)
#resolution  : 1, 1  (x, y)
#extent      : -0.5, 449.5, -0.5, 4171.5  (xmin, xmax, ymin, ymax)
#coord. ref. :  
#sources     : longitude  
#              latitude  
#              nitrogendioxide_tropospheric_column  
#varnames    : longitude (pixel center longitude) 
#              latitude (pixel center latitude) 
#              nitrogendioxide_tropospheric_column (Tropospheric vertical column of nitrogen dioxide) 
#names       :    longitude,      latitude, nitrogendi~ric_column 
#unit        : degrees_east, degrees_north,               mol m-2 
#time        : 2020-01-07 

plot(r, nr=1)

该图说明数据不是按常规栅格数据组织的(如果是这样,则纬度为N-S渐变,经度为E-W渐变)。另请参阅plot(r$longitude, r$latitude)。您可以将其视为积分:

dp <- as.data.frame(r)
p <- vect(dp, geom=c("longitude", "latitude"))

绘制需要一段时间,因为有>;150万个点,所以我抽取了一个样本

plot(p[sample(nrow(p), 10000)], "nitrogendioxide_tropospheric_column")

如果希望将数据组织为常规栅格,可以使用rasterize

x <- rast(res=1/6)
x <- rasterize(p, x, "nitrogendioxide_tropospheric_column", fun=mean)
plot(x > 0)

你可以像这样得到安大略省

can <- vect(raster::getData("GADM", country="CAN", level=1))
ontario <- can[can$NAME_1=="Ontario", ]

x <- crop(x, ontario)
x <- mask(x, ontario)
plot(x)

这篇关于从R中的netcdf创建栅格最准确的方法是什么?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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